details

property	value
status	complete
benchmark	plus.pl
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n149.star.cs.uiowa.edu
space	SGST06

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	1.81560611725 seconds
cpu usage	3.993226071
max memory	2.79564288E8

stage attributes

key	value
output-size	6347
starexec-result	YES

output

/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.pl /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.pl # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Left Termination of the query pattern plus(g,a,a) w.r.t. the given Prolog program could successfully be proven: (0) Prolog (1) PrologToPiTRSProof [SOUND, 0 ms] (2) PiTRS (3) DependencyPairsProof [EQUIVALENT, 0 ms] (4) PiDP (5) DependencyGraphProof [EQUIVALENT, 0 ms] (6) PiDP (7) UsableRulesProof [EQUIVALENT, 0 ms] (8) PiDP (9) PiDPToQDPProof [SOUND, 0 ms] (10) QDP (11) QDPSizeChangeProof [EQUIVALENT, 0 ms] (12) YES ---------------------------------------- (0) Obligation: Clauses: plus(0, Y, Y). plus(s(X), Y, Z) :- plus(X, s(Y), Z). Query: plus(g,a,a) ---------------------------------------- (1) PrologToPiTRSProof (SOUND) We use the technique of [TOCL09]. With regard to the inferred argument filtering the predicates were used in the following modes: plus_in_3: (b,f,f) Transforming Prolog into the following Term Rewriting System: Pi-finite rewrite system: The TRS R consists of the following rules: plus_in_gaa(0, Y, Y) -> plus_out_gaa(0, Y, Y) plus_in_gaa(s(X), Y, Z) -> U1_gaa(X, Y, Z, plus_in_gaa(X, s(Y), Z)) U1_gaa(X, Y, Z, plus_out_gaa(X, s(Y), Z)) -> plus_out_gaa(s(X), Y, Z) The argument filtering Pi contains the following mapping: plus_in_gaa(x1, x2, x3) = plus_in_gaa(x1) 0 = 0 plus_out_gaa(x1, x2, x3) = plus_out_gaa s(x1) = s(x1) U1_gaa(x1, x2, x3, x4) = U1_gaa(x4) Infinitary Constructor Rewriting Termination of PiTRS implies Termination of Prolog ---------------------------------------- (2) Obligation: Pi-finite rewrite system: The TRS R consists of the following rules: plus_in_gaa(0, Y, Y) -> plus_out_gaa(0, Y, Y) plus_in_gaa(s(X), Y, Z) -> U1_gaa(X, Y, Z, plus_in_gaa(X, s(Y), Z)) U1_gaa(X, Y, Z, plus_out_gaa(X, s(Y), Z)) -> plus_out_gaa(s(X), Y, Z) The argument filtering Pi contains the following mapping: plus_in_gaa(x1, x2, x3) = plus_in_gaa(x1) 0 = 0 plus_out_gaa(x1, x2, x3) = plus_out_gaa s(x1) = s(x1) U1_gaa(x1, x2, x3, x4) = U1_gaa(x4) popout

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