details

property	value
status	complete
benchmark	palindrome.pl
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n139.star.cs.uiowa.edu
space	talp_talp

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	1.97416186333 seconds
cpu usage	4.193857268
max memory	3.08289536E8

stage attributes

key	value
output-size	10658
starexec-result	YES

output

/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.pl /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.pl # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Left Termination of the query pattern palindrome(g) w.r.t. the given Prolog program could successfully be proven: (0) Prolog (1) PrologToPiTRSProof [SOUND, 0 ms] (2) PiTRS (3) DependencyPairsProof [EQUIVALENT, 0 ms] (4) PiDP (5) DependencyGraphProof [EQUIVALENT, 0 ms] (6) PiDP (7) UsableRulesProof [EQUIVALENT, 0 ms] (8) PiDP (9) PiDPToQDPProof [EQUIVALENT, 0 ms] (10) QDP (11) QDPSizeChangeProof [EQUIVALENT, 0 ms] (12) YES ---------------------------------------- (0) Obligation: Clauses: palindrome(Xs) :- reverse(Xs, Xs). reverse(X1s, X2s) :- reverse3(X1s, [], X2s). reverse3(.(X, X1s), X2s, Ys) :- reverse3(X1s, .(X, X2s), Ys). reverse3([], Xs, Xs). Query: palindrome(g) ---------------------------------------- (1) PrologToPiTRSProof (SOUND) We use the technique of [TOCL09]. With regard to the inferred argument filtering the predicates were used in the following modes: palindrome_in_1: (b) reverse_in_2: (b,b) reverse3_in_3: (b,b,b) Transforming Prolog into the following Term Rewriting System: Pi-finite rewrite system: The TRS R consists of the following rules: palindrome_in_g(Xs) -> U1_g(Xs, reverse_in_gg(Xs, Xs)) reverse_in_gg(X1s, X2s) -> U2_gg(X1s, X2s, reverse3_in_ggg(X1s, [], X2s)) reverse3_in_ggg(.(X, X1s), X2s, Ys) -> U3_ggg(X, X1s, X2s, Ys, reverse3_in_ggg(X1s, .(X, X2s), Ys)) reverse3_in_ggg([], Xs, Xs) -> reverse3_out_ggg([], Xs, Xs) U3_ggg(X, X1s, X2s, Ys, reverse3_out_ggg(X1s, .(X, X2s), Ys)) -> reverse3_out_ggg(.(X, X1s), X2s, Ys) U2_gg(X1s, X2s, reverse3_out_ggg(X1s, [], X2s)) -> reverse_out_gg(X1s, X2s) U1_g(Xs, reverse_out_gg(Xs, Xs)) -> palindrome_out_g(Xs) The argument filtering Pi contains the following mapping: palindrome_in_g(x1) = palindrome_in_g(x1) U1_g(x1, x2) = U1_g(x2) reverse_in_gg(x1, x2) = reverse_in_gg(x1, x2) U2_gg(x1, x2, x3) = U2_gg(x3) reverse3_in_ggg(x1, x2, x3) = reverse3_in_ggg(x1, x2, x3) .(x1, x2) = .(x1, x2) U3_ggg(x1, x2, x3, x4, x5) = U3_ggg(x5) [] = [] reverse3_out_ggg(x1, x2, x3) = reverse3_out_ggg reverse_out_gg(x1, x2) = reverse_out_gg palindrome_out_g(x1) = palindrome_out_g Infinitary Constructor Rewriting Termination of PiTRS implies Termination of Prolog popout

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