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TRS Conditional pair #487562855
details
property
value
status
complete
benchmark
272.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n023.star.cs.uiowa.edu
space
COPS
run statistics
property
value
solver
muterm 6.0.3
configuration
default
runtime (wallclock)
0.0272271633148 seconds
cpu usage
0.023324691
max memory
2355200.0
stage attributes
key
value
output-size
10312
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR v_NonEmpty:S l:S m:S n:S) (RULES insert(cons(n:S,l:S),m:S) -> cons(m:S,cons(n:S,l:S)) | lte(m:S,n:S) ->* ttrue insert(cons(n:S,l:S),m:S) -> cons(n:S,insert(l:S,m:S)) | lte(m:S,n:S) ->* ffalse insert(nil,m:S) -> cons(m:S,nil) lte(0,n:S) -> ttrue lte(s(m:S),0) -> ffalse lte(s(m:S),s(n:S)) -> lte(m:S,n:S) ordered(cons(m:S,cons(n:S,l:S))) -> ordered(cons(n:S,l:S)) | lte(m:S,n:S) ->* ttrue ordered(cons(m:S,cons(n:S,l:S))) -> ffalse | lte(m:S,n:S) ->* ffalse ordered(cons(m:S,nil)) -> ttrue ordered(nil) -> ttrue ) Problem 1: Valid CTRS Processor: -> Rules: insert(cons(n:S,l:S),m:S) -> cons(m:S,cons(n:S,l:S)) | lte(m:S,n:S) ->* ttrue insert(cons(n:S,l:S),m:S) -> cons(n:S,insert(l:S,m:S)) | lte(m:S,n:S) ->* ffalse insert(nil,m:S) -> cons(m:S,nil) lte(0,n:S) -> ttrue lte(s(m:S),0) -> ffalse lte(s(m:S),s(n:S)) -> lte(m:S,n:S) ordered(cons(m:S,cons(n:S,l:S))) -> ordered(cons(n:S,l:S)) | lte(m:S,n:S) ->* ttrue ordered(cons(m:S,cons(n:S,l:S))) -> ffalse | lte(m:S,n:S) ->* ffalse ordered(cons(m:S,nil)) -> ttrue ordered(nil) -> ttrue -> The system is a deterministic 3-CTRS. Problem 1: Dependency Pairs Processor: Conditional Termination Problem 1: -> Pairs: INSERT(cons(n:S,l:S),m:S) -> INSERT(l:S,m:S) | lte(m:S,n:S) ->* ffalse LTE(s(m:S),s(n:S)) -> LTE(m:S,n:S) ORDERED(cons(m:S,cons(n:S,l:S))) -> ORDERED(cons(n:S,l:S)) | lte(m:S,n:S) ->* ttrue -> QPairs: Empty -> Rules: insert(cons(n:S,l:S),m:S) -> cons(m:S,cons(n:S,l:S)) | lte(m:S,n:S) ->* ttrue insert(cons(n:S,l:S),m:S) -> cons(n:S,insert(l:S,m:S)) | lte(m:S,n:S) ->* ffalse insert(nil,m:S) -> cons(m:S,nil) lte(0,n:S) -> ttrue lte(s(m:S),0) -> ffalse lte(s(m:S),s(n:S)) -> lte(m:S,n:S) ordered(cons(m:S,cons(n:S,l:S))) -> ordered(cons(n:S,l:S)) | lte(m:S,n:S) ->* ttrue ordered(cons(m:S,cons(n:S,l:S))) -> ffalse | lte(m:S,n:S) ->* ffalse ordered(cons(m:S,nil)) -> ttrue ordered(nil) -> ttrue Conditional Termination Problem 2: -> Pairs: INSERT(cons(n:S,l:S),m:S) -> LTE(m:S,n:S) ORDERED(cons(m:S,cons(n:S,l:S))) -> LTE(m:S,n:S) -> QPairs: LTE(s(m:S),s(n:S)) -> LTE(m:S,n:S) -> Rules: insert(cons(n:S,l:S),m:S) -> cons(m:S,cons(n:S,l:S)) | lte(m:S,n:S) ->* ttrue insert(cons(n:S,l:S),m:S) -> cons(n:S,insert(l:S,m:S)) | lte(m:S,n:S) ->* ffalse insert(nil,m:S) -> cons(m:S,nil) lte(0,n:S) -> ttrue lte(s(m:S),0) -> ffalse lte(s(m:S),s(n:S)) -> lte(m:S,n:S) ordered(cons(m:S,cons(n:S,l:S))) -> ordered(cons(n:S,l:S)) | lte(m:S,n:S) ->* ttrue ordered(cons(m:S,cons(n:S,l:S))) -> ffalse | lte(m:S,n:S) ->* ffalse ordered(cons(m:S,nil)) -> ttrue ordered(nil) -> ttrue The problem is decomposed in 2 subproblems. Problem 1.1: SCC Processor: -> Pairs: INSERT(cons(n:S,l:S),m:S) -> INSERT(l:S,m:S) | lte(m:S,n:S) ->* ffalse LTE(s(m:S),s(n:S)) -> LTE(m:S,n:S) ORDERED(cons(m:S,cons(n:S,l:S))) -> ORDERED(cons(n:S,l:S)) | lte(m:S,n:S) ->* ttrue -> QPairs: Empty -> Rules: insert(cons(n:S,l:S),m:S) -> cons(m:S,cons(n:S,l:S)) | lte(m:S,n:S) ->* ttrue insert(cons(n:S,l:S),m:S) -> cons(n:S,insert(l:S,m:S)) | lte(m:S,n:S) ->* ffalse insert(nil,m:S) -> cons(m:S,nil) lte(0,n:S) -> ttrue lte(s(m:S),0) -> ffalse lte(s(m:S),s(n:S)) -> lte(m:S,n:S) ordered(cons(m:S,cons(n:S,l:S))) -> ordered(cons(n:S,l:S)) | lte(m:S,n:S) ->* ttrue
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