details

property	value
status	complete
benchmark	324.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n142.star.cs.uiowa.edu
space	COPS

run statistics

property	value
solver	muterm 6.0.3
configuration	default
runtime (wallclock)	101.054668903 seconds
cpu usage	100.90535853
max memory	3.52751616E8

stage attributes

key	value
output-size	3182
starexec-result	NO

output

/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- NO Problem 1: (VAR v_NonEmpty:S x:S) (RULES eq(x:S,x:S) -> eq(T,T) even(0) -> ttrue even(s(x:S)) -> ffalse | eq(odd(x:S),ffalse) ->* eq(T,T) even(s(x:S)) -> ttrue | eq(odd(x:S),ttrue) ->* eq(T,T) odd(0) -> ffalse odd(s(x:S)) -> ffalse | eq(even(x:S),ffalse) ->* eq(T,T) odd(s(x:S)) -> ttrue | eq(even(x:S),ttrue) ->* eq(T,T) ) Problem 1: Valid CTRS Processor: -> Rules: eq(x:S,x:S) -> eq(T,T) even(0) -> ttrue even(s(x:S)) -> ffalse | eq(odd(x:S),ffalse) ->* eq(T,T) even(s(x:S)) -> ttrue | eq(odd(x:S),ttrue) ->* eq(T,T) odd(0) -> ffalse odd(s(x:S)) -> ffalse | eq(even(x:S),ffalse) ->* eq(T,T) odd(s(x:S)) -> ttrue | eq(even(x:S),ttrue) ->* eq(T,T) -> The system is a deterministic 3-CTRS. Problem 1: Dependency Pairs Processor: Conditional Termination Problem 1: -> Pairs: EQ(x:S,x:S) -> EQ(T,T) -> QPairs: Empty -> Rules: eq(x:S,x:S) -> eq(T,T) even(0) -> ttrue even(s(x:S)) -> ffalse | eq(odd(x:S),ffalse) ->* eq(T,T) even(s(x:S)) -> ttrue | eq(odd(x:S),ttrue) ->* eq(T,T) odd(0) -> ffalse odd(s(x:S)) -> ffalse | eq(even(x:S),ffalse) ->* eq(T,T) odd(s(x:S)) -> ttrue | eq(even(x:S),ttrue) ->* eq(T,T) Conditional Termination Problem 2: -> Pairs: EVEN(s(x:S)) -> EQ(odd(x:S),ffalse) EVEN(s(x:S)) -> EQ(odd(x:S),ttrue) EVEN(s(x:S)) -> ODD(x:S) ODD(s(x:S)) -> EQ(even(x:S),ffalse) ODD(s(x:S)) -> EQ(even(x:S),ttrue) ODD(s(x:S)) -> EVEN(x:S) -> QPairs: EQ(x:S,x:S) -> EQ(T,T) -> Rules: eq(x:S,x:S) -> eq(T,T) even(0) -> ttrue even(s(x:S)) -> ffalse | eq(odd(x:S),ffalse) ->* eq(T,T) even(s(x:S)) -> ttrue | eq(odd(x:S),ttrue) ->* eq(T,T) odd(0) -> ffalse odd(s(x:S)) -> ffalse | eq(even(x:S),ffalse) ->* eq(T,T) odd(s(x:S)) -> ttrue | eq(even(x:S),ttrue) ->* eq(T,T) Problem 1: SCC Processor: -> Pairs: EQ(x:S,x:S) -> EQ(T,T) -> QPairs: Empty -> Rules: eq(x:S,x:S) -> eq(T,T) even(0) -> ttrue even(s(x:S)) -> ffalse | eq(odd(x:S),ffalse) ->* eq(T,T) even(s(x:S)) -> ttrue | eq(odd(x:S),ttrue) ->* eq(T,T) odd(0) -> ffalse odd(s(x:S)) -> ffalse | eq(even(x:S),ffalse) ->* eq(T,T) odd(s(x:S)) -> ttrue | eq(even(x:S),ttrue) ->* eq(T,T) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: EQ(x:S,x:S) -> EQ(T,T) -> QPairs: Empty ->->-> Rules: eq(x:S,x:S) -> eq(T,T) even(0) -> ttrue even(s(x:S)) -> ffalse | eq(odd(x:S),ffalse) ->* eq(T,T) even(s(x:S)) -> ttrue | eq(odd(x:S),ttrue) ->* eq(T,T) odd(0) -> ffalse odd(s(x:S)) -> ffalse | eq(even(x:S),ffalse) ->* eq(T,T) odd(s(x:S)) -> ttrue | eq(even(x:S),ttrue) ->* eq(T,T) popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to TRS Conditional