details

property	value
status	complete
benchmark	plus1.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n144.star.cs.uiowa.edu
space	Mixed_CTRS_2014

run statistics

property	value
solver	muterm 6.0.3
configuration	default
runtime (wallclock)	0.0645060539246 seconds
cpu usage	0.01877128
max memory	1519616.0

stage attributes

key	value
output-size	2213
starexec-result	YES

output

/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR v_NonEmpty:S x:S y:S z:S) (RULES plus(0,x:S) -> x:S plus(s(x:S),y:S) -> s(z:S) | plus(x:S,y:S) ->* z:S plus(x:S,0) -> x:S ) Problem 1: Valid CTRS Processor: -> Rules: plus(0,x:S) -> x:S plus(s(x:S),y:S) -> s(z:S) | plus(x:S,y:S) ->* z:S plus(x:S,0) -> x:S -> The system is a deterministic 3-CTRS. Problem 1: Dependency Pairs Processor: Conditional Termination Problem 1: -> Pairs: Empty -> QPairs: Empty -> Rules: plus(0,x:S) -> x:S plus(s(x:S),y:S) -> s(z:S) | plus(x:S,y:S) ->* z:S plus(x:S,0) -> x:S Conditional Termination Problem 2: -> Pairs: PLUS(s(x:S),y:S) -> PLUS(x:S,y:S) -> QPairs: Empty -> Rules: plus(0,x:S) -> x:S plus(s(x:S),y:S) -> s(z:S) | plus(x:S,y:S) ->* z:S plus(x:S,0) -> x:S The problem is decomposed in 2 subproblems. Problem 1.1: SCC Processor: -> Pairs: Empty -> QPairs: Empty -> Rules: plus(0,x:S) -> x:S plus(s(x:S),y:S) -> s(z:S) | plus(x:S,y:S) ->* z:S plus(x:S,0) -> x:S ->Strongly Connected Components: There is no strongly connected component The problem is finite. Problem 1.2: SCC Processor: -> Pairs: PLUS(s(x:S),y:S) -> PLUS(x:S,y:S) -> QPairs: Empty -> Rules: plus(0,x:S) -> x:S plus(s(x:S),y:S) -> s(z:S) | plus(x:S,y:S) ->* z:S plus(x:S,0) -> x:S ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: PLUS(s(x:S),y:S) -> PLUS(x:S,y:S) -> QPairs: Empty ->->-> Rules: plus(0,x:S) -> x:S plus(s(x:S),y:S) -> s(z:S) | plus(x:S,y:S) ->* z:S plus(x:S,0) -> x:S Problem 1.2: Conditional Subterm Processor: -> Pairs: PLUS(s(x:S),y:S) -> PLUS(x:S,y:S) -> QPairs: Empty -> Rules: plus(0,x:S) -> x:S plus(s(x:S),y:S) -> s(z:S) | plus(x:S,y:S) ->* z:S popout

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job log

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actions

all output return to TRS Conditional