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C Integer pair #487569530
details
property
value
status
complete
benchmark
KroeningSharyginaTsitovichWintersteiger-CAV2010-Ex_true-termination.c
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n098.star.cs.uiowa.edu
space
Stroeder_15
run statistics
property
value
solver
AProVE
configuration
c
runtime (wallclock)
2.43121886253 seconds
cpu usage
6.208939878
max memory
4.59116544E8
stage attributes
key
value
output-size
3048
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_c /export/starexec/sandbox2/benchmark/theBenchmark.c /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.c # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination of the given C Problem could be proven: (0) C Problem (1) CToIRSProof [EQUIVALENT, 0 ms] (2) IntTRS (3) TerminationGraphProcessor [SOUND, 49 ms] (4) IntTRS (5) IntTRSCompressionProof [EQUIVALENT, 21 ms] (6) IntTRS (7) PolynomialOrderProcessor [EQUIVALENT, 10 ms] (8) IntTRS (9) RankingReductionPairProof [EQUIVALENT, 0 ms] (10) YES ---------------------------------------- (0) Obligation: c file /export/starexec/sandbox2/benchmark/theBenchmark.c ---------------------------------------- (1) CToIRSProof (EQUIVALENT) Parsed C Integer Program as IRS. ---------------------------------------- (2) Obligation: Rules: f1(i) -> f2(x_1) :|: TRUE f4(x) -> f7(arith) :|: TRUE && arith = x + 1 f5(x11) -> f8(x12) :|: TRUE && x12 = x11 + 2 f3(x2) -> f4(x2) :|: x3 < 0 f3(x13) -> f4(x13) :|: x14 > 0 f3(x4) -> f5(x4) :|: x5 = 0 f7(x6) -> f6(x6) :|: TRUE f8(x7) -> f6(x7) :|: TRUE f2(x8) -> f3(x8) :|: x8 < 255 f6(x9) -> f2(x9) :|: TRUE f2(x10) -> f9(x10) :|: x10 >= 255 Start term: f1(i) ---------------------------------------- (3) TerminationGraphProcessor (SOUND) Constructed the termination graph and obtained one non-trivial SCC. ---------------------------------------- (4) Obligation: Rules: f2(x8) -> f3(x8) :|: x8 < 255 f6(x9) -> f2(x9) :|: TRUE f7(x6) -> f6(x6) :|: TRUE f4(x) -> f7(arith) :|: TRUE && arith = x + 1 f3(x2) -> f4(x2) :|: x3 < 0 f3(x13) -> f4(x13) :|: x14 > 0 f8(x7) -> f6(x7) :|: TRUE f5(x11) -> f8(x12) :|: TRUE && x12 = x11 + 2 f3(x4) -> f5(x4) :|: x5 = 0 ---------------------------------------- (5) IntTRSCompressionProof (EQUIVALENT) Compressed rules. ---------------------------------------- (6) Obligation: Rules: f6(x9:0) -> f6(x9:0 + 1) :|: x9:0 < 255 && x3:0 < 0 f6(x) -> f6(x + 1) :|: x < 255 && x1 > 0 f6(x2) -> f6(x2 + 2) :|: x2 < 255 ---------------------------------------- (7) PolynomialOrderProcessor (EQUIVALENT) Found the following polynomial interpretation: [f6(x)] = 65024 - 510*x + x^2 The following rules are decreasing: f6(x9:0) -> f6(x9:0 + 1) :|: x9:0 < 255 && x3:0 < 0 f6(x) -> f6(x + 1) :|: x < 255 && x1 > 0 The following rules are bounded: f6(x9:0) -> f6(x9:0 + 1) :|: x9:0 < 255 && x3:0 < 0 f6(x) -> f6(x + 1) :|: x < 255 && x1 > 0 f6(x2) -> f6(x2 + 2) :|: x2 < 255
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