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TRS Standard pair #516961134
details
property
value
status
complete
benchmark
Ex15_Luc06_C.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n002.star.cs.uiowa.edu
space
Transformed_CSR_04
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
1.17351913452 seconds
cpu usage
2.485147364
max memory
2.72867328E8
stage attributes
key
value
output-size
12594
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: active(f(f(a()))) -> mark(f(g(f(a())))) active(g(X)) -> g(active(X)) g(mark(X)) -> mark(g(X)) proper(f(X)) -> f(proper(X)) proper(a()) -> ok(a()) proper(g(X)) -> g(proper(X)) f(ok(X)) -> ok(f(X)) g(ok(X)) -> ok(g(X)) top(mark(X)) -> top(proper(X)) top(ok(X)) -> top(active(X)) Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 0 1] [0] [mark](x0) = [0 0 1]x0 + [0] [0 0 0] [1], [1 1 0] [f](x0) = [0 0 1]x0 [0 1 0] , [1 0 1] [0] [g](x0) = [0 0 1]x0 + [0] [0 0 0] [1], [proper](x0) = x0 , [0] [a] = [0] [1], [1 0 0] [top](x0) = [0 0 0]x0 [0 0 0] , [ok](x0) = x0 , [active](x0) = x0 orientation: [1] [0] active(f(f(a()))) = [0] >= [0] = mark(f(g(f(a())))) [1] [1] [1 0 1] [0] [1 0 1] [0] active(g(X)) = [0 0 1]X + [0] >= [0 0 1]X + [0] = g(active(X)) [0 0 0] [1] [0 0 0] [1] [1 0 1] [1] [1 0 1] [1] g(mark(X)) = [0 0 0]X + [1] >= [0 0 0]X + [1] = mark(g(X)) [0 0 0] [1] [0 0 0] [1] [1 1 0] [1 1 0] proper(f(X)) = [0 0 1]X >= [0 0 1]X = f(proper(X)) [0 1 0] [0 1 0] [0] [0] proper(a()) = [0] >= [0] = ok(a()) [1] [1] [1 0 1] [0] [1 0 1] [0] proper(g(X)) = [0 0 1]X + [0] >= [0 0 1]X + [0] = g(proper(X)) [0 0 0] [1] [0 0 0] [1] [1 1 0] [1 1 0] f(ok(X)) = [0 0 1]X >= [0 0 1]X = ok(f(X)) [0 1 0] [0 1 0] [1 0 1] [0] [1 0 1] [0] g(ok(X)) = [0 0 1]X + [0] >= [0 0 1]X + [0] = ok(g(X)) [0 0 0] [1] [0 0 0] [1] [1 0 1] [1 0 0] top(mark(X)) = [0 0 0]X >= [0 0 0]X = top(proper(X)) [0 0 0] [0 0 0] [1 0 0] [1 0 0] top(ok(X)) = [0 0 0]X >= [0 0 0]X = top(active(X)) [0 0 0] [0 0 0] problem: active(g(X)) -> g(active(X)) g(mark(X)) -> mark(g(X)) proper(f(X)) -> f(proper(X)) proper(a()) -> ok(a())
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