details

property	value
status	complete
benchmark	Ex14_AEGL02_FR.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n028.star.cs.uiowa.edu
space	Transformed_CSR_04

run statistics

property	value
solver	AProVE21
configuration	standard
runtime (wallclock)	11.4725818634 seconds
cpu usage	30.722700868
max memory	1.7859584E9

stage attributes

key	value
output-size	13421
starexec-result	NO

output

/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 mhark 20210624 unpublished Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) DependencyPairsProof [EQUIVALENT, 16 ms] (2) QDP (3) DependencyGraphProof [EQUIVALENT, 0 ms] (4) AND (5) QDP (6) UsableRulesProof [EQUIVALENT, 0 ms] (7) QDP (8) QDPSizeChangeProof [EQUIVALENT, 0 ms] (9) YES (10) QDP (11) TransformationProof [EQUIVALENT, 0 ms] (12) QDP (13) TransformationProof [EQUIVALENT, 0 ms] (14) QDP (15) DependencyGraphProof [EQUIVALENT, 0 ms] (16) QDP (17) QDPOrderProof [EQUIVALENT, 38 ms] (18) QDP (19) NonTerminationLoopProof [COMPLETE, 0 ms] (20) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: from(X) -> cons(X, n__from(n__s(X))) length(n__nil) -> 0 length(n__cons(X, Y)) -> s(length1(activate(Y))) length1(X) -> length(activate(X)) from(X) -> n__from(X) s(X) -> n__s(X) nil -> n__nil cons(X1, X2) -> n__cons(X1, X2) activate(n__from(X)) -> from(activate(X)) activate(n__s(X)) -> s(activate(X)) activate(n__nil) -> nil activate(n__cons(X1, X2)) -> cons(activate(X1), X2) activate(X) -> X Q is empty. ---------------------------------------- (1) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (2) Obligation: Q DP problem: The TRS P consists of the following rules: FROM(X) -> CONS(X, n__from(n__s(X))) LENGTH(n__cons(X, Y)) -> S(length1(activate(Y))) LENGTH(n__cons(X, Y)) -> LENGTH1(activate(Y)) LENGTH(n__cons(X, Y)) -> ACTIVATE(Y) LENGTH1(X) -> LENGTH(activate(X)) LENGTH1(X) -> ACTIVATE(X) ACTIVATE(n__from(X)) -> FROM(activate(X)) ACTIVATE(n__from(X)) -> ACTIVATE(X) ACTIVATE(n__s(X)) -> S(activate(X)) ACTIVATE(n__s(X)) -> ACTIVATE(X) ACTIVATE(n__nil) -> NIL ACTIVATE(n__cons(X1, X2)) -> CONS(activate(X1), X2) ACTIVATE(n__cons(X1, X2)) -> ACTIVATE(X1) The TRS R consists of the following rules: from(X) -> cons(X, n__from(n__s(X))) length(n__nil) -> 0 length(n__cons(X, Y)) -> s(length1(activate(Y))) length1(X) -> length(activate(X)) from(X) -> n__from(X) s(X) -> n__s(X) nil -> n__nil cons(X1, X2) -> n__cons(X1, X2) activate(n__from(X)) -> from(activate(X)) activate(n__s(X)) -> s(activate(X)) activate(n__nil) -> nil activate(n__cons(X1, X2)) -> cons(activate(X1), X2) activate(X) -> X popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to TRS Standard