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TRS Standard pair #516961669
details
property
value
status
complete
benchmark
Ex24_Luc06_FR.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n061.star.cs.uiowa.edu
space
Transformed_CSR_04
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
0.566406011581 seconds
cpu usage
1.076806713
max memory
1.7143808E8
stage attributes
key
value
output-size
1155
starexec-result
NO
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- NO Problem: f(n__b(),X,n__c()) -> f(X,c(),X) c() -> b() b() -> n__b() c() -> n__c() activate(n__b()) -> b() activate(n__c()) -> c() activate(X) -> X Proof: Matrix Interpretation Processor: dim=1 interpretation: [b] = 6, [n__c] = 6, [c] = 6, [activate](x0) = 4x0 + 6, [n__b] = 6, [f](x0, x1, x2) = 2x0 + 3x1 + x2 + 4 orientation: f(n__b(),X,n__c()) = 3X + 22 >= 3X + 22 = f(X,c(),X) c() = 6 >= 6 = b() b() = 6 >= 6 = n__b() c() = 6 >= 6 = n__c() activate(n__b()) = 30 >= 6 = b() activate(n__c()) = 30 >= 6 = c() activate(X) = 4X + 6 >= X = X problem: f(n__b(),X,n__c()) -> f(X,c(),X) c() -> b() b() -> n__b() c() -> n__c() Unfolding Processor: loop length: 4 terms: f(c(),c(),c()) f(c(),c(),n__c()) f(b(),c(),n__c()) f(n__b(),c(),n__c()) context: [] substitution: Qed
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