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TRS Standard pair #516962525
details
property
value
status
complete
benchmark
Ex14_Luc06_L.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n172.star.cs.uiowa.edu
space
Transformed_CSR_04
run statistics
property
value
solver
AProVE21
configuration
standard
runtime (wallclock)
3.60346484184 seconds
cpu usage
11.069797491
max memory
1.151737856E9
stage attributes
key
value
output-size
4475
starexec-result
NO
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 mhark 20210624 unpublished Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) QTRSRRRProof [EQUIVALENT, 48 ms] (2) QTRS (3) AAECC Innermost [EQUIVALENT, 0 ms] (4) QTRS (5) DependencyPairsProof [EQUIVALENT, 0 ms] (6) QDP (7) UsableRulesProof [EQUIVALENT, 0 ms] (8) QDP (9) QReductionProof [EQUIVALENT, 0 ms] (10) QDP (11) NonTerminationLoopProof [COMPLETE, 2 ms] (12) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: h(X) -> g(X) g(a) -> f(b) f(X) -> h(a) a -> b Q is empty. ---------------------------------------- (1) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(a) = 1 POL(b) = 0 POL(f(x_1)) = 1 + x_1 POL(g(x_1)) = x_1 POL(h(x_1)) = x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: a -> b ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: h(X) -> g(X) g(a) -> f(b) f(X) -> h(a) Q is empty. ---------------------------------------- (3) AAECC Innermost (EQUIVALENT) We have applied [NOC,AAECCNOC] to switch to innermost. The TRS R 1 is none The TRS R 2 is h(X) -> g(X) g(a) -> f(b) f(X) -> h(a) The signature Sigma is {h_1, g_1, f_1} ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: h(X) -> g(X) g(a) -> f(b) f(X) -> h(a) The set Q consists of the following terms: h(x0) g(a) f(x0)
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