Spaces
Explore
Communities
Statistics
Reports
Cluster
Status
Help
TRS Standard pair #516964079
details
property
value
status
complete
benchmark
26.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n071.star.cs.uiowa.edu
space
Various_04
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
0.693382978439 seconds
cpu usage
1.064763786
max memory
1.68865792E8
stage attributes
key
value
output-size
4176
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: f(f(x)) -> f(g(f(x),x)) f(f(x)) -> f(h(f(x),f(x))) g(x,y) -> y h(x,x) -> g(x,0()) Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1 0 0] [1] [g](x0, x1) = [0 0 0]x0 + [0 1 1]x1 + [0] [0 0 0] [0 0 1] [0], [0] [0] = [0] [0], [1 0 1] [0] [f](x0) = [0 0 0]x0 + [0] [1 0 1] [1], [1 0 0] [1 0 0] [1] [h](x0, x1) = [0 1 0]x0 + [0 0 0]x1 + [0] [0 0 0] [0 0 0] [0] orientation: [2 0 2] [1] [2 0 2] [1] f(f(x)) = [0 0 0]x + [0] >= [0 0 0]x + [0] = f(g(f(x),x)) [2 0 2] [2] [2 0 2] [2] [2 0 2] [1] [2 0 2] [1] f(f(x)) = [0 0 0]x + [0] >= [0 0 0]x + [0] = f(h(f(x),f(x))) [2 0 2] [2] [2 0 2] [2] [1 0 0] [1 0 0] [1] g(x,y) = [0 0 0]x + [0 1 1]y + [0] >= y = y [0 0 0] [0 0 1] [0] [2 0 0] [1] [1 0 0] [1] h(x,x) = [0 1 0]x + [0] >= [0 0 0]x + [0] = g(x,0()) [0 0 0] [0] [0 0 0] [0] problem: f(f(x)) -> f(g(f(x),x)) f(f(x)) -> f(h(f(x),f(x))) h(x,x) -> g(x,0()) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1 0 1] [g](x0, x1) = [0 1 0]x0 + [0 0 0]x1 [0 0 0] [0 0 0] , [0] [0] = [0] [0], [1 0 1] [0] [f](x0) = [0 1 0]x0 + [0] [1 1 1] [1], [1 1 0] [1 0 0] [0] [h](x0, x1) = [0 0 0]x0 + [0 1 0]x1 + [0] [0 0 0] [0 0 0] [1] orientation: [2 1 2] [1] [2 0 2] [0] f(f(x)) = [0 1 0]x + [0] >= [0 1 0]x + [0] = f(g(f(x),x)) [2 2 2] [2] [2 1 2] [1] [2 1 2] [1] [2 1 2] [1] f(f(x)) = [0 1 0]x + [0] >= [0 1 0]x + [0] = f(h(f(x),f(x))) [2 2 2] [2] [2 2 2] [2] [2 1 0] [0] [1 0 0] h(x,x) = [0 1 0]x + [0] >= [0 1 0]x = g(x,0()) [0 0 0] [1] [0 0 0] problem: f(f(x)) -> f(h(f(x),f(x))) h(x,x) -> g(x,0()) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1 0 0] [g](x0, x1) = [0 0 0]x0 + [0 0 0]x1 [0 0 0] [0 0 0] , [0] [0] = [0] [0], [1 1 1] [0] [f](x0) = [1 1 1]x0 + [0] [0 0 0] [1],
popout
output may be truncated. 'popout' for the full output.
job log
popout
actions
all output
return to TRS Standard