details

property	value
status	complete
benchmark	02.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n140.star.cs.uiowa.edu
space	Der95

run statistics

property	value
solver	ttt2-1.20
configuration	ttt2
runtime (wallclock)	0.432819843292 seconds
cpu usage	0.665158969
max memory	1.482752E8

stage attributes

key	value
output-size	2083
starexec-result	YES

output

/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: .(1(),x) -> x .(x,1()) -> x .(i(x),x) -> 1() .(x,i(x)) -> 1() i(1()) -> 1() i(i(x)) -> x .(i(y),.(y,z)) -> z .(y,.(i(y),z)) -> z Proof: Matrix Interpretation Processor: dim=1 interpretation: [.](x0, x1) = x0 + x1 + 3, [1] = 6, [i](x0) = 2x0 + 3 orientation: .(1(),x) = x + 9 >= x = x .(x,1()) = x + 9 >= x = x .(i(x),x) = 3x + 6 >= 6 = 1() .(x,i(x)) = 3x + 6 >= 6 = 1() i(1()) = 15 >= 6 = 1() i(i(x)) = 4x + 9 >= x = x .(i(y),.(y,z)) = 3y + z + 9 >= z = z .(y,.(i(y),z)) = 3y + z + 9 >= z = z problem: .(i(x),x) -> 1() .(x,i(x)) -> 1() Matrix Interpretation Processor: dim=3 interpretation: [1 1 0] [1 0 0] [1] [.](x0, x1) = [0 0 1]x0 + [0 0 0]x1 + [0] [0 1 0] [0 0 0] [1], [1] [1] = [0] [1], [1 1 1] [0] [i](x0) = [0 0 0]x0 + [1] [1 0 0] [0] orientation: [2 1 1] [2] [1] .(i(x),x) = [1 0 0]x + [0] >= [0] = 1() [0 0 0] [2] [1] [2 2 1] [1] [1] .(x,i(x)) = [0 0 1]x + [0] >= [0] = 1() [0 1 0] [1] [1] problem: .(x,i(x)) -> 1() Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1 0 0] [1] [.](x0, x1) = [1 0 0]x0 + [0 0 0]x1 + [0] [0 0 0] [0 0 1] [0], [0] [1] = [0] [1], [1 0 0] [0] [i](x0) = [0 0 0]x0 + [0] [0 0 0] [1] orientation: [2 0 0] [1] [0] .(x,i(x)) = [1 0 0]x + [0] >= [0] = 1() [0 0 0] [1] [1] problem: Qed popout

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