details

property	value
status	complete
benchmark	perfect.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n169.star.cs.uiowa.edu
space	Mixed_TRS

run statistics

property	value
solver	muterm 6.0.3
configuration	default
runtime (wallclock)	0.0965859889984 seconds
cpu usage	0.021424718
max memory	1744896.0

stage attributes

key	value
output-size	3384
starexec-result	YES

output

/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR v_NonEmpty:S u:S x:S y:S z:S) (RULES f(0,y:S,0,u:S) -> ttrue f(0,y:S,s(z:S),u:S) -> ffalse f(s(x:S),0,z:S,u:S) -> f(x:S,u:S,minus(z:S,s(x:S)),u:S) f(s(x:S),s(y:S),z:S,u:S) -> if(le(x:S,y:S),f(s(x:S),minus(y:S,x:S),z:S,u:S),f(x:S,u:S,z:S,u:S)) perfectp(0) -> ffalse perfectp(s(x:S)) -> f(x:S,s(0),s(x:S),s(x:S)) ) Problem 1: Innermost Equivalent Processor: -> Rules: f(0,y:S,0,u:S) -> ttrue f(0,y:S,s(z:S),u:S) -> ffalse f(s(x:S),0,z:S,u:S) -> f(x:S,u:S,minus(z:S,s(x:S)),u:S) f(s(x:S),s(y:S),z:S,u:S) -> if(le(x:S,y:S),f(s(x:S),minus(y:S,x:S),z:S,u:S),f(x:S,u:S,z:S,u:S)) perfectp(0) -> ffalse perfectp(s(x:S)) -> f(x:S,s(0),s(x:S),s(x:S)) -> The term rewriting system is non-overlaping or locally confluent overlay system. Therefore, innermost termination implies termination. Problem 1: Dependency Pairs Processor: -> Pairs: F(s(x:S),0,z:S,u:S) -> F(x:S,u:S,minus(z:S,s(x:S)),u:S) F(s(x:S),s(y:S),z:S,u:S) -> F(x:S,u:S,z:S,u:S) PERFECTP(s(x:S)) -> F(x:S,s(0),s(x:S),s(x:S)) -> Rules: f(0,y:S,0,u:S) -> ttrue f(0,y:S,s(z:S),u:S) -> ffalse f(s(x:S),0,z:S,u:S) -> f(x:S,u:S,minus(z:S,s(x:S)),u:S) f(s(x:S),s(y:S),z:S,u:S) -> if(le(x:S,y:S),f(s(x:S),minus(y:S,x:S),z:S,u:S),f(x:S,u:S,z:S,u:S)) perfectp(0) -> ffalse perfectp(s(x:S)) -> f(x:S,s(0),s(x:S),s(x:S)) Problem 1: SCC Processor: -> Pairs: F(s(x:S),0,z:S,u:S) -> F(x:S,u:S,minus(z:S,s(x:S)),u:S) F(s(x:S),s(y:S),z:S,u:S) -> F(x:S,u:S,z:S,u:S) PERFECTP(s(x:S)) -> F(x:S,s(0),s(x:S),s(x:S)) -> Rules: f(0,y:S,0,u:S) -> ttrue f(0,y:S,s(z:S),u:S) -> ffalse f(s(x:S),0,z:S,u:S) -> f(x:S,u:S,minus(z:S,s(x:S)),u:S) f(s(x:S),s(y:S),z:S,u:S) -> if(le(x:S,y:S),f(s(x:S),minus(y:S,x:S),z:S,u:S),f(x:S,u:S,z:S,u:S)) perfectp(0) -> ffalse perfectp(s(x:S)) -> f(x:S,s(0),s(x:S),s(x:S)) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: F(s(x:S),0,z:S,u:S) -> F(x:S,u:S,minus(z:S,s(x:S)),u:S) F(s(x:S),s(y:S),z:S,u:S) -> F(x:S,u:S,z:S,u:S) ->->-> Rules: f(0,y:S,0,u:S) -> ttrue f(0,y:S,s(z:S),u:S) -> ffalse f(s(x:S),0,z:S,u:S) -> f(x:S,u:S,minus(z:S,s(x:S)),u:S) f(s(x:S),s(y:S),z:S,u:S) -> if(le(x:S,y:S),f(s(x:S),minus(y:S,x:S),z:S,u:S),f(x:S,u:S,z:S,u:S)) perfectp(0) -> ffalse perfectp(s(x:S)) -> f(x:S,s(0),s(x:S),s(x:S)) Problem 1: Subterm Processor: -> Pairs: F(s(x:S),0,z:S,u:S) -> F(x:S,u:S,minus(z:S,s(x:S)),u:S) F(s(x:S),s(y:S),z:S,u:S) -> F(x:S,u:S,z:S,u:S) -> Rules: f(0,y:S,0,u:S) -> ttrue f(0,y:S,s(z:S),u:S) -> ffalse f(s(x:S),0,z:S,u:S) -> f(x:S,u:S,minus(z:S,s(x:S)),u:S) f(s(x:S),s(y:S),z:S,u:S) -> if(le(x:S,y:S),f(s(x:S),minus(y:S,x:S),z:S,u:S),f(x:S,u:S,z:S,u:S)) perfectp(0) -> ffalse perfectp(s(x:S)) -> f(x:S,s(0),s(x:S),s(x:S)) ->Projection: pi(F) = 1 Problem 1: SCC Processor: -> Pairs: Empty -> Rules: f(0,y:S,0,u:S) -> ttrue f(0,y:S,s(z:S),u:S) -> ffalse f(s(x:S),0,z:S,u:S) -> f(x:S,u:S,minus(z:S,s(x:S)),u:S) popout

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