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TRS Standard pair #516964519
details
property
value
status
complete
benchmark
jones1.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n074.star.cs.uiowa.edu
space
Mixed_TRS
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
0.476475954056 seconds
cpu usage
0.655917456
max memory
1.72875776E8
stage attributes
key
value
output-size
3248
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: rev(ls) -> r1(ls,empty()) r1(empty(),a) -> a r1(cons(x,k),a) -> r1(k,cons(x,a)) Proof: Matrix Interpretation Processor: dim=3 interpretation: [0] [empty] = [0] [1], [1 0 0] [1 0 0] [1] [cons](x0, x1) = [0 0 0]x0 + [0 0 0]x1 + [1] [0 0 0] [0 1 1] [0], [1 0 1] [0] [rev](x0) = [1 1 1]x0 + [0] [1 0 0] [1], [1 0 1] [1 0 0] [r1](x0, x1) = [1 0 0]x0 + [0 1 0]x1 [1 0 0] [0 1 1] orientation: [1 0 1] [0] [1 0 1] [0] rev(ls) = [1 1 1]ls + [0] >= [1 0 0]ls + [0] = r1(ls,empty()) [1 0 0] [1] [1 0 0] [1] [1 0 0] [1] r1(empty(),a) = [0 1 0]a + [0] >= a = a [0 1 1] [0] [1 0 0] [1 1 1] [1 0 0] [1] [1 0 0] [1 0 1] [1 0 0] [1] r1(cons(x,k),a) = [0 1 0]a + [1 0 0]k + [1 0 0]x + [1] >= [0 0 0]a + [1 0 0]k + [0 0 0]x + [1] = r1(k,cons(x,a)) [0 1 1] [1 0 0] [1 0 0] [1] [0 1 1] [1 0 0] [0 0 0] [1] problem: rev(ls) -> r1(ls,empty()) r1(cons(x,k),a) -> r1(k,cons(x,a)) Matrix Interpretation Processor: dim=3 interpretation: [0] [empty] = [0] [0], [1 0 0] [1 0 0] [0] [cons](x0, x1) = [0 0 0]x0 + [0 0 0]x1 + [0] [0 0 0] [0 0 1] [1], [1 0 1] [rev](x0) = [0 0 0]x0 [0 0 0] , [1 0 1] [1 0 0] [r1](x0, x1) = [0 0 0]x0 + [0 0 0]x1 [0 0 0] [0 0 0] orientation: [1 0 1] [1 0 1] rev(ls) = [0 0 0]ls >= [0 0 0]ls = r1(ls,empty()) [0 0 0] [0 0 0] [1 0 0] [1 0 1] [1 0 0] [1] [1 0 0] [1 0 1] [1 0 0] r1(cons(x,k),a) = [0 0 0]a + [0 0 0]k + [0 0 0]x + [0] >= [0 0 0]a + [0 0 0]k + [0 0 0]x = r1(k,cons(x,a)) [0 0 0] [0 0 0] [0 0 0] [0] [0 0 0] [0 0 0] [0 0 0] problem: rev(ls) -> r1(ls,empty()) Matrix Interpretation Processor: dim=3 interpretation: [0] [empty] = [1] [0], [1 0 0] [1] [rev](x0) = [0 0 0]x0 + [0] [0 0 0] [1], [1 0 0] [1 0 0] [r1](x0, x1) = [0 0 0]x0 + [0 0 0]x1 [0 0 0] [0 1 0] orientation: [1 0 0] [1] [1 0 0] [0] rev(ls) = [0 0 0]ls + [0] >= [0 0 0]ls + [0] = r1(ls,empty()) [0 0 0] [1] [0 0 0] [1] problem: Qed
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