details

property	value
status	complete
benchmark	003.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n082.star.cs.uiowa.edu
space	AotoYamada_05

run statistics

property	value
solver	NTI_22
configuration	default
runtime (wallclock)	0.415152072906 seconds
cpu usage	0.702843245
max memory	6.690816E7

stage attributes

key	value
output-size	2694
starexec-result	NO

output

/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO ** BEGIN proof argument ** The following rule was generated while unfolding the analyzed TRS: [iteration = 0] app(app(app(until,_0),_1),_2) -> app(app(app(until,_0),_1),app(_1,_2)) Let l be the left-hand side and r be the right-hand side of this rule. Let p = epsilon, theta1 = {} and theta2 = {_2->app(_1,_2)}. We have r|p = app(app(app(until,_0),_1),app(_1,_2)) and theta2(theta1(l)) = theta1(r|p). Hence, the term theta1(l) = app(app(app(until,_0),_1),_2) loops w.r.t. the analyzed TRS. ** END proof argument ** ** BEGIN proof description ** ## Searching for a generalized rewrite rule (a rule whose right-hand side contains a variable that does not occur in the left-hand side)... No generalized rewrite rule found! ## Applying the DP framework... ## 1 initial DP problem to solve. ## First, we try to decompose this problem into smaller problems. ## Round 1 [1 DP problem]: ## DP problem: Dependency pairs = [app^#(app(app(until,_0),_1),_2) -> app^#(app(app(if,app(_0,_2)),_2),app(app(app(until,_0),_1),app(_1,_2))), app^#(app(app(until,_0),_1),_2) -> app^#(app(if,app(_0,_2)),_2), app^#(app(app(until,_0),_1),_2) -> app^#(_0,_2), app^#(app(app(until,_0),_1),_2) -> app^#(app(app(until,_0),_1),app(_1,_2)), app^#(app(app(until,_0),_1),_2) -> app^#(app(until,_0),_1), app^#(app(app(until,_0),_1),_2) -> app^#(_1,_2)] TRS = {app(app(app(if,true),_0),_1) -> _0, app(app(app(if,false),_0),_1) -> _1, app(app(app(until,_0),_1),_2) -> app(app(app(if,app(_0,_2)),_2),app(app(app(until,_0),_1),app(_1,_2)))} ## Trying with homeomorphic embeddings... Failed! ## Trying with polynomial interpretations... Failed! ## Trying with lexicographic path orders... Failed! ## Trying with Knuth-Bendix orders... Failed! Don't know whether this DP problem is finite. ## A DP problem could not be proved finite. ## Now, we try to prove that this problem is infinite. ## Trying to find a loop (forward=true, backward=true, max=20) # max_depth=20, unfold_variables=false: # Iteration 0: success, found a loop, 4 unfolded rules generated. Here is the successful unfolding. Let IR be the TRS under analysis. L0 = app^#(app(app(until,_0),_1),_2) -> app^#(app(app(until,_0),_1),app(_1,_2)) [trans] is in U_IR^0. This DP problem is infinite. Proof run on Linux version 3.10.0-1160.25.1.el7.x86_64 for amd64 using Java version 1.8.0_292 ** END proof description ** Total number of generated unfolded rules = 4 popout

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actions

all output return to TRS Standard