details

property	value
status	complete
benchmark	jw29.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n071.star.cs.uiowa.edu
space	Zantema_05

run statistics

property	value
solver	ttt2-1.20
configuration	ttt2
runtime (wallclock)	0.455908060074 seconds
cpu usage	0.55863398
max memory	1.37998336E8

stage attributes

key	value
output-size	2679
starexec-result	YES

output

/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: f(f(a(),a()),x) -> f(x,f(f(a(),f(a(),a())),a())) Proof: Extended Uncurrying Processor: application symbol: f symbol table: a ==> a0/0 a1/1 a2/2 uncurry-rules: f(a1(x1),x2) -> a2(x1,x2) f(a0(),x1) -> a1(x1) eta-rules: problem: a2(a0(),x) -> f(x,a2(a1(a0()),a0())) f(a1(x1),x2) -> a2(x1,x2) f(a0(),x1) -> a1(x1) Matrix Interpretation Processor: dim=3 interpretation: [1 1 0] [1 0 1] [a2](x0, x1) = [0 0 0]x0 + [0 0 0]x1 [0 0 0] [0 0 0] , [1 0 1] [1 1 1] [f](x0, x1) = [0 0 0]x0 + [1 0 0]x1 [0 0 0] [0 1 1] , [1 0 0] [a1](x0) = [0 0 0]x0 [0 1 1] , [0] [a0] = [1] [0] orientation: [1 0 1] [1] [1 0 1] a2(a0(),x) = [0 0 0]x + [0] >= [0 0 0]x = f(x,a2(a1(a0()),a0())) [0 0 0] [0] [0 0 0] [1 1 1] [1 1 1] [1 1 0] [1 0 1] f(a1(x1),x2) = [0 0 0]x1 + [1 0 0]x2 >= [0 0 0]x1 + [0 0 0]x2 = a2(x1,x2) [0 0 0] [0 1 1] [0 0 0] [0 0 0] [1 1 1] [1 0 0] f(a0(),x1) = [1 0 0]x1 >= [0 0 0]x1 = a1(x1) [0 1 1] [0 1 1] problem: f(a1(x1),x2) -> a2(x1,x2) f(a0(),x1) -> a1(x1) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1 0 0] [a2](x0, x1) = [0 0 0]x0 + [0 0 0]x1 [0 0 0] [0 0 0] , [1 0 0] [1 0 0] [1] [f](x0, x1) = [0 0 0]x0 + [0 0 0]x1 + [0] [0 0 0] [0 0 0] [0], [1 0 0] [a1](x0) = [0 0 0]x0 [0 0 0] , [0] [a0] = [0] [0] orientation: [1 0 0] [1 0 0] [1] [1 0 0] [1 0 0] f(a1(x1),x2) = [0 0 0]x1 + [0 0 0]x2 + [0] >= [0 0 0]x1 + [0 0 0]x2 = a2(x1,x2) [0 0 0] [0 0 0] [0] [0 0 0] [0 0 0] [1 0 0] [1] [1 0 0] f(a0(),x1) = [0 0 0]x1 + [0] >= [0 0 0]x1 = a1(x1) [0 0 0] [0] [0 0 0] problem: Qed popout

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