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TRS Standard pair #516965761
details
property
value
status
complete
benchmark
pair2simple1.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n001.star.cs.uiowa.edu
space
Endrullis_06
run statistics
property
value
solver
muterm 6.0.3
configuration
default
runtime (wallclock)
1.60259890556 seconds
cpu usage
1.54629307
max memory
5.0782208E7
stage attributes
key
value
output-size
2825
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR v_NonEmpty:S x0:S x1:S x2:S) (RULES p(a(x0:S),p(a(b(x1:S)),x2:S)) -> p(a(b(a(x2:S))),p(a(a(x1:S)),x2:S)) ) Problem 1: Dependency Pairs Processor: -> Pairs: P(a(x0:S),p(a(b(x1:S)),x2:S)) -> P(a(a(x1:S)),x2:S) P(a(x0:S),p(a(b(x1:S)),x2:S)) -> P(a(b(a(x2:S))),p(a(a(x1:S)),x2:S)) -> Rules: p(a(x0:S),p(a(b(x1:S)),x2:S)) -> p(a(b(a(x2:S))),p(a(a(x1:S)),x2:S)) Problem 1: SCC Processor: -> Pairs: P(a(x0:S),p(a(b(x1:S)),x2:S)) -> P(a(a(x1:S)),x2:S) P(a(x0:S),p(a(b(x1:S)),x2:S)) -> P(a(b(a(x2:S))),p(a(a(x1:S)),x2:S)) -> Rules: p(a(x0:S),p(a(b(x1:S)),x2:S)) -> p(a(b(a(x2:S))),p(a(a(x1:S)),x2:S)) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: P(a(x0:S),p(a(b(x1:S)),x2:S)) -> P(a(a(x1:S)),x2:S) P(a(x0:S),p(a(b(x1:S)),x2:S)) -> P(a(b(a(x2:S))),p(a(a(x1:S)),x2:S)) ->->-> Rules: p(a(x0:S),p(a(b(x1:S)),x2:S)) -> p(a(b(a(x2:S))),p(a(a(x1:S)),x2:S)) Problem 1: Reduction Pair Processor: -> Pairs: P(a(x0:S),p(a(b(x1:S)),x2:S)) -> P(a(a(x1:S)),x2:S) P(a(x0:S),p(a(b(x1:S)),x2:S)) -> P(a(b(a(x2:S))),p(a(a(x1:S)),x2:S)) -> Rules: p(a(x0:S),p(a(b(x1:S)),x2:S)) -> p(a(b(a(x2:S))),p(a(a(x1:S)),x2:S)) -> Usable rules: p(a(x0:S),p(a(b(x1:S)),x2:S)) -> p(a(b(a(x2:S))),p(a(a(x1:S)),x2:S)) ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [p](X1,X2) = 2.X1 + 2.X2 + 2 [a](X) = 2 [b](X) = 2 [P](X1,X2) = X1 + 2.X2 Problem 1: SCC Processor: -> Pairs: P(a(x0:S),p(a(b(x1:S)),x2:S)) -> P(a(b(a(x2:S))),p(a(a(x1:S)),x2:S)) -> Rules: p(a(x0:S),p(a(b(x1:S)),x2:S)) -> p(a(b(a(x2:S))),p(a(a(x1:S)),x2:S)) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: P(a(x0:S),p(a(b(x1:S)),x2:S)) -> P(a(b(a(x2:S))),p(a(a(x1:S)),x2:S)) ->->-> Rules: p(a(x0:S),p(a(b(x1:S)),x2:S)) -> p(a(b(a(x2:S))),p(a(a(x1:S)),x2:S)) Problem 1: Reduction Pair Processor: -> Pairs: P(a(x0:S),p(a(b(x1:S)),x2:S)) -> P(a(b(a(x2:S))),p(a(a(x1:S)),x2:S)) -> Rules: p(a(x0:S),p(a(b(x1:S)),x2:S)) -> p(a(b(a(x2:S))),p(a(a(x1:S)),x2:S)) -> Usable rules: p(a(x0:S),p(a(b(x1:S)),x2:S)) -> p(a(b(a(x2:S))),p(a(a(x1:S)),x2:S)) ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 2 ->Bound: 1 ->Interpretation: [p](X1,X2) = [0 1;0 0].X1 + [1 1;1 1].X2 [a](X) = [0 0;1 0].X + [0;1]
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