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TRS Standard pair #516966098
details
property
value
status
complete
benchmark
divExp.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n053.star.cs.uiowa.edu
space
Secret_06_TRS
run statistics
property
value
solver
NaTT 2.1
configuration
default
runtime (wallclock)
0.231147050858 seconds
cpu usage
0.193378191
max memory
1.8395136E7
stage attributes
key
value
output-size
1925
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Input TRS: 1: minus(x,x) -> 0() 2: minus(s(x),s(y)) -> minus(x,y) 3: minus(0(),x) -> 0() 4: minus(x,0()) -> x 5: div(s(x),s(y)) -> s(div(minus(x,y),s(y))) 6: div(0(),s(y)) -> 0() 7: f(x,0(),b) -> x 8: f(x,s(y),b) -> div(f(x,minus(s(y),s(0())),b),b) Number of strict rules: 8 Direct poly ... failed. Freezing ... failed. Dependency Pairs: #1: #minus(s(x),s(y)) -> #minus(x,y) #2: #div(s(x),s(y)) -> #div(minus(x,y),s(y)) #3: #div(s(x),s(y)) -> #minus(x,y) #4: #f(x,s(y),b) -> #div(f(x,minus(s(y),s(0())),b),b) #5: #f(x,s(y),b) -> #f(x,minus(s(y),s(0())),b) #6: #f(x,s(y),b) -> #minus(s(y),s(0())) Number of SCCs: 3, DPs: 3 SCC { #1 } Sum... succeeded. #div(x1,x2) w: (0) s(x1) w: (1 + x1) minus(x1,x2) w: (0) div(x1,x2) w: (0) f(x1,x2,x3) w: (0) 0() w: (0) #f(x1,x2,x3) w: (0) #minus(x1,x2) w: (x2 + x1) USABLE RULES: { } Removed DPs: #1 Number of SCCs: 2, DPs: 2 SCC { #2 } Sum... succeeded. #div(x1,x2) w: (8855 + x1) s(x1) w: (2439 + x1) minus(x1,x2) w: (1 + x1) div(x1,x2) w: (0) f(x1,x2,x3) w: (0) 0() w: (1) #f(x1,x2,x3) w: (0) #minus(x1,x2) w: (0) USABLE RULES: { 1..4 } Removed DPs: #2 Number of SCCs: 1, DPs: 1 SCC { #5 } Sum... Max... QLPOpS... NegMaxSum... QWPOpSMaxSum... 2D-Mat... sum_sum_int,sum_neg... succeeded. #div(x1,x2) w: (0, 0) s(x1) w: (max{0, 29245 + x1_1}, -29245 + x1_2) minus(x1,x2) w: (max{0, 2 + x2_2 + x1_1}, 0) div(x1,x2) w: (0, 0) f(x1,x2,x3) w: (0, 0) 0() w: (0, -1) #f(x1,x2,x3) w: (max{0, 29243 + x2_1}, 0) #minus(x1,x2) w: (0, 0) USABLE RULES: { 1..4 } Removed DPs: #5 Number of SCCs: 0, DPs: 0
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