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TRS Standard pair #516966229
details
property
value
status
complete
benchmark
7.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n144.star.cs.uiowa.edu
space
Secret_06_TRS
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
0.549938201904 seconds
cpu usage
1.131709607
max memory
2.50646528E8
stage attributes
key
value
output-size
1538
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: c(c(c(a(x,y)))) -> b(c(c(c(c(y)))),x) c(c(b(c(y),0()))) -> a(0(),c(c(a(y,0())))) c(c(a(a(y,0()),x))) -> c(y) Proof: Matrix Interpretation Processor: dim=1 interpretation: [c](x0) = 2x0, [0] = 1, [a](x0, x1) = x0 + 2x1, [b](x0, x1) = x0 + 6x1 orientation: c(c(c(a(x,y)))) = 8x + 16y >= 6x + 16y = b(c(c(c(c(y)))),x) c(c(b(c(y),0()))) = 8y + 24 >= 8y + 17 = a(0(),c(c(a(y,0())))) c(c(a(a(y,0()),x))) = 8x + 4y + 8 >= 2y = c(y) problem: c(c(c(a(x,y)))) -> b(c(c(c(c(y)))),x) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [c](x0) = [0 1 1]x0 [0 0 0] , [1 0 0] [1 0 0] [1] [a](x0, x1) = [0 0 0]x0 + [0 0 0]x1 + [1] [0 0 0] [0 0 0] [0], [1 0 0] [1 0 0] [0] [b](x0, x1) = [0 0 0]x0 + [0 0 0]x1 + [1] [0 0 0] [0 0 0] [0] orientation: [1 0 0] [1 0 0] [1] [1 0 0] [1 0 0] [0] c(c(c(a(x,y)))) = [0 0 0]x + [0 0 0]y + [1] >= [0 0 0]x + [0 0 0]y + [1] = b(c(c(c(c(y)))),x) [0 0 0] [0 0 0] [0] [0 0 0] [0 0 0] [0] problem: Qed
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