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TRS Standard pair #516966676
details
property
value
status
complete
benchmark
4.61.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n073.star.cs.uiowa.edu
space
SK90
run statistics
property
value
solver
muterm 6.0.3
configuration
default
runtime (wallclock)
7.86652708054 seconds
cpu usage
7.825876083
max memory
1.15458048E8
stage attributes
key
value
output-size
13011
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR v_NonEmpty:S x:S y:S z:S) (RULES bsort(.(x:S,y:S)) -> last(.(bubble(.(x:S,y:S)),bsort(butlast(bubble(.(x:S,y:S)))))) bsort(nil) -> nil bubble(.(x:S,.(y:S,z:S))) -> if(<=(x:S,y:S),.(y:S,bubble(.(x:S,z:S))),.(x:S,bubble(.(y:S,z:S)))) bubble(.(x:S,nil)) -> .(x:S,nil) bubble(nil) -> nil butlast(.(x:S,.(y:S,z:S))) -> .(x:S,butlast(.(y:S,z:S))) butlast(.(x:S,nil)) -> nil butlast(nil) -> nil last(.(x:S,.(y:S,z:S))) -> last(.(y:S,z:S)) last(.(x:S,nil)) -> x:S last(nil) -> 0 ) Problem 1: Innermost Equivalent Processor: -> Rules: bsort(.(x:S,y:S)) -> last(.(bubble(.(x:S,y:S)),bsort(butlast(bubble(.(x:S,y:S)))))) bsort(nil) -> nil bubble(.(x:S,.(y:S,z:S))) -> if(<=(x:S,y:S),.(y:S,bubble(.(x:S,z:S))),.(x:S,bubble(.(y:S,z:S)))) bubble(.(x:S,nil)) -> .(x:S,nil) bubble(nil) -> nil butlast(.(x:S,.(y:S,z:S))) -> .(x:S,butlast(.(y:S,z:S))) butlast(.(x:S,nil)) -> nil butlast(nil) -> nil last(.(x:S,.(y:S,z:S))) -> last(.(y:S,z:S)) last(.(x:S,nil)) -> x:S last(nil) -> 0 -> The term rewriting system is non-overlaping or locally confluent overlay system. Therefore, innermost termination implies termination. Problem 1: Dependency Pairs Processor: -> Pairs: BSORT(.(x:S,y:S)) -> BSORT(butlast(bubble(.(x:S,y:S)))) BSORT(.(x:S,y:S)) -> BUBBLE(.(x:S,y:S)) BSORT(.(x:S,y:S)) -> BUTLAST(bubble(.(x:S,y:S))) BSORT(.(x:S,y:S)) -> LAST(.(bubble(.(x:S,y:S)),bsort(butlast(bubble(.(x:S,y:S)))))) BUBBLE(.(x:S,.(y:S,z:S))) -> BUBBLE(.(x:S,z:S)) BUBBLE(.(x:S,.(y:S,z:S))) -> BUBBLE(.(y:S,z:S)) BUTLAST(.(x:S,.(y:S,z:S))) -> BUTLAST(.(y:S,z:S)) LAST(.(x:S,.(y:S,z:S))) -> LAST(.(y:S,z:S)) -> Rules: bsort(.(x:S,y:S)) -> last(.(bubble(.(x:S,y:S)),bsort(butlast(bubble(.(x:S,y:S)))))) bsort(nil) -> nil bubble(.(x:S,.(y:S,z:S))) -> if(<=(x:S,y:S),.(y:S,bubble(.(x:S,z:S))),.(x:S,bubble(.(y:S,z:S)))) bubble(.(x:S,nil)) -> .(x:S,nil) bubble(nil) -> nil butlast(.(x:S,.(y:S,z:S))) -> .(x:S,butlast(.(y:S,z:S))) butlast(.(x:S,nil)) -> nil butlast(nil) -> nil last(.(x:S,.(y:S,z:S))) -> last(.(y:S,z:S)) last(.(x:S,nil)) -> x:S last(nil) -> 0 Problem 1: SCC Processor: -> Pairs: BSORT(.(x:S,y:S)) -> BSORT(butlast(bubble(.(x:S,y:S)))) BSORT(.(x:S,y:S)) -> BUBBLE(.(x:S,y:S)) BSORT(.(x:S,y:S)) -> BUTLAST(bubble(.(x:S,y:S))) BSORT(.(x:S,y:S)) -> LAST(.(bubble(.(x:S,y:S)),bsort(butlast(bubble(.(x:S,y:S)))))) BUBBLE(.(x:S,.(y:S,z:S))) -> BUBBLE(.(x:S,z:S)) BUBBLE(.(x:S,.(y:S,z:S))) -> BUBBLE(.(y:S,z:S)) BUTLAST(.(x:S,.(y:S,z:S))) -> BUTLAST(.(y:S,z:S)) LAST(.(x:S,.(y:S,z:S))) -> LAST(.(y:S,z:S)) -> Rules: bsort(.(x:S,y:S)) -> last(.(bubble(.(x:S,y:S)),bsort(butlast(bubble(.(x:S,y:S)))))) bsort(nil) -> nil bubble(.(x:S,.(y:S,z:S))) -> if(<=(x:S,y:S),.(y:S,bubble(.(x:S,z:S))),.(x:S,bubble(.(y:S,z:S)))) bubble(.(x:S,nil)) -> .(x:S,nil) bubble(nil) -> nil butlast(.(x:S,.(y:S,z:S))) -> .(x:S,butlast(.(y:S,z:S))) butlast(.(x:S,nil)) -> nil butlast(nil) -> nil last(.(x:S,.(y:S,z:S))) -> last(.(y:S,z:S)) last(.(x:S,nil)) -> x:S last(nil) -> 0 ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: LAST(.(x:S,.(y:S,z:S))) -> LAST(.(y:S,z:S)) ->->-> Rules: bsort(.(x:S,y:S)) -> last(.(bubble(.(x:S,y:S)),bsort(butlast(bubble(.(x:S,y:S)))))) bsort(nil) -> nil bubble(.(x:S,.(y:S,z:S))) -> if(<=(x:S,y:S),.(y:S,bubble(.(x:S,z:S))),.(x:S,bubble(.(y:S,z:S))))
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