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TRS Standard pair #516966789
details
property
value
status
complete
benchmark
2.56.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n128.star.cs.uiowa.edu
space
SK90
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
0.40078997612 seconds
cpu usage
0.491260161
max memory
1.16211712E8
stage attributes
key
value
output-size
1933
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: f(a(),x) -> g(a(),x) g(a(),x) -> f(b(),x) f(a(),x) -> f(b(),x) Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 0 1] [1 0 0] [0] [f](x0, x1) = [0 0 0]x0 + [0 0 0]x1 + [0] [0 0 0] [0 0 0] [1], [0] [b] = [0] [0], [0] [a] = [0] [1], [1 0 0] [1 0 0] [0] [g](x0, x1) = [0 0 0]x0 + [0 0 0]x1 + [0] [0 0 0] [0 0 0] [1] orientation: [1 0 0] [1] [1 0 0] [0] f(a(),x) = [0 0 0]x + [0] >= [0 0 0]x + [0] = g(a(),x) [0 0 0] [1] [0 0 0] [1] [1 0 0] [0] [1 0 0] [0] g(a(),x) = [0 0 0]x + [0] >= [0 0 0]x + [0] = f(b(),x) [0 0 0] [1] [0 0 0] [1] [1 0 0] [1] [1 0 0] [0] f(a(),x) = [0 0 0]x + [0] >= [0 0 0]x + [0] = f(b(),x) [0 0 0] [1] [0 0 0] [1] problem: g(a(),x) -> f(b(),x) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1 0 0] [f](x0, x1) = [0 0 0]x0 + [0 0 0]x1 [0 0 0] [0 0 0] , [0] [b] = [0] [0], [0] [a] = [1] [0], [1 1 0] [1 0 0] [g](x0, x1) = [0 0 0]x0 + [0 0 0]x1 [0 0 0] [0 0 0] orientation: [1 0 0] [1] [1 0 0] g(a(),x) = [0 0 0]x + [0] >= [0 0 0]x = f(b(),x) [0 0 0] [0] [0 0 0] problem: Qed
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