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TRS Standard pair #516966830
details
property
value
status
complete
benchmark
2.58.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n045.star.cs.uiowa.edu
space
SK90
run statistics
property
value
solver
AProVE21
configuration
standard
runtime (wallclock)
2.12391710281 seconds
cpu usage
5.573392195
max memory
4.72375296E8
stage attributes
key
value
output-size
2797
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 mhark 20210624 unpublished Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRSRRRProof [EQUIVALENT, 40 ms] (2) QTRS (3) QTRSRRRProof [EQUIVALENT, 8 ms] (4) QTRS (5) QTRSRRRProof [EQUIVALENT, 0 ms] (6) QTRS (7) RisEmptyProof [EQUIVALENT, 0 ms] (8) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(x, y) -> x g(a) -> h(a, b, a) i(x) -> f(x, x) h(x, x, y) -> g(x) Q is empty. ---------------------------------------- (1) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(a) = 0 POL(b) = 0 POL(f(x_1, x_2)) = 2 + x_1 + x_2 POL(g(x_1)) = x_1 POL(h(x_1, x_2, x_3)) = 2*x_1 + 2*x_2 + x_3 POL(i(x_1)) = 2 + 2*x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: f(x, y) -> x ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: g(a) -> h(a, b, a) i(x) -> f(x, x) h(x, x, y) -> g(x) Q is empty. ---------------------------------------- (3) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(a) = 0 POL(b) = 0 POL(f(x_1, x_2)) = x_1 + x_2 POL(g(x_1)) = x_1 POL(h(x_1, x_2, x_3)) = 2*x_1 + 2*x_2 + x_3 POL(i(x_1)) = 2 + 2*x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: i(x) -> f(x, x) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: g(a) -> h(a, b, a) h(x, x, y) -> g(x) Q is empty.
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