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TRS Standard pair #516967221
details
property
value
status
complete
benchmark
#3.55.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n144.star.cs.uiowa.edu
space
AG01
run statistics
property
value
solver
muterm 6.0.3
configuration
default
runtime (wallclock)
0.153969049454 seconds
cpu usage
0.114597436
max memory
5042176.0
stage attributes
key
value
output-size
30583
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR v_NonEmpty:S m:S n:S x:S y:S) (RULES app(add(n:S,x:S),y:S) -> add(n:S,app(x:S,y:S)) app(nil,y:S) -> y:S high(n:S,add(m:S,x:S)) -> if_high(le(m:S,n:S),n:S,add(m:S,x:S)) high(n:S,nil) -> nil if_high(ffalse,n:S,add(m:S,x:S)) -> add(m:S,high(n:S,x:S)) if_high(ttrue,n:S,add(m:S,x:S)) -> high(n:S,x:S) if_low(ffalse,n:S,add(m:S,x:S)) -> low(n:S,x:S) if_low(ttrue,n:S,add(m:S,x:S)) -> add(m:S,low(n:S,x:S)) le(0,y:S) -> ttrue le(s(x:S),0) -> ffalse le(s(x:S),s(y:S)) -> le(x:S,y:S) low(n:S,add(m:S,x:S)) -> if_low(le(m:S,n:S),n:S,add(m:S,x:S)) low(n:S,nil) -> nil minus(s(x:S),s(y:S)) -> minus(x:S,y:S) minus(x:S,0) -> x:S quicksort(add(n:S,x:S)) -> app(quicksort(low(n:S,x:S)),add(n:S,quicksort(high(n:S,x:S)))) quicksort(nil) -> nil quot(0,s(y:S)) -> 0 quot(s(x:S),s(y:S)) -> s(quot(minus(x:S,y:S),s(y:S))) ) Problem 1: Innermost Equivalent Processor: -> Rules: app(add(n:S,x:S),y:S) -> add(n:S,app(x:S,y:S)) app(nil,y:S) -> y:S high(n:S,add(m:S,x:S)) -> if_high(le(m:S,n:S),n:S,add(m:S,x:S)) high(n:S,nil) -> nil if_high(ffalse,n:S,add(m:S,x:S)) -> add(m:S,high(n:S,x:S)) if_high(ttrue,n:S,add(m:S,x:S)) -> high(n:S,x:S) if_low(ffalse,n:S,add(m:S,x:S)) -> low(n:S,x:S) if_low(ttrue,n:S,add(m:S,x:S)) -> add(m:S,low(n:S,x:S)) le(0,y:S) -> ttrue le(s(x:S),0) -> ffalse le(s(x:S),s(y:S)) -> le(x:S,y:S) low(n:S,add(m:S,x:S)) -> if_low(le(m:S,n:S),n:S,add(m:S,x:S)) low(n:S,nil) -> nil minus(s(x:S),s(y:S)) -> minus(x:S,y:S) minus(x:S,0) -> x:S quicksort(add(n:S,x:S)) -> app(quicksort(low(n:S,x:S)),add(n:S,quicksort(high(n:S,x:S)))) quicksort(nil) -> nil quot(0,s(y:S)) -> 0 quot(s(x:S),s(y:S)) -> s(quot(minus(x:S,y:S),s(y:S))) -> The term rewriting system is non-overlaping or locally confluent overlay system. Therefore, innermost termination implies termination. Problem 1: Dependency Pairs Processor: -> Pairs: APP(add(n:S,x:S),y:S) -> APP(x:S,y:S) HIGH(n:S,add(m:S,x:S)) -> IF_HIGH(le(m:S,n:S),n:S,add(m:S,x:S)) HIGH(n:S,add(m:S,x:S)) -> LE(m:S,n:S) IF_HIGH(ffalse,n:S,add(m:S,x:S)) -> HIGH(n:S,x:S) IF_HIGH(ttrue,n:S,add(m:S,x:S)) -> HIGH(n:S,x:S) IF_LOW(ffalse,n:S,add(m:S,x:S)) -> LOW(n:S,x:S) IF_LOW(ttrue,n:S,add(m:S,x:S)) -> LOW(n:S,x:S) LE(s(x:S),s(y:S)) -> LE(x:S,y:S) LOW(n:S,add(m:S,x:S)) -> IF_LOW(le(m:S,n:S),n:S,add(m:S,x:S)) LOW(n:S,add(m:S,x:S)) -> LE(m:S,n:S) MINUS(s(x:S),s(y:S)) -> MINUS(x:S,y:S) QUICKSORT(add(n:S,x:S)) -> APP(quicksort(low(n:S,x:S)),add(n:S,quicksort(high(n:S,x:S)))) QUICKSORT(add(n:S,x:S)) -> HIGH(n:S,x:S) QUICKSORT(add(n:S,x:S)) -> LOW(n:S,x:S) QUICKSORT(add(n:S,x:S)) -> QUICKSORT(high(n:S,x:S)) QUICKSORT(add(n:S,x:S)) -> QUICKSORT(low(n:S,x:S)) QUOT(s(x:S),s(y:S)) -> MINUS(x:S,y:S) QUOT(s(x:S),s(y:S)) -> QUOT(minus(x:S,y:S),s(y:S)) -> Rules: app(add(n:S,x:S),y:S) -> add(n:S,app(x:S,y:S)) app(nil,y:S) -> y:S high(n:S,add(m:S,x:S)) -> if_high(le(m:S,n:S),n:S,add(m:S,x:S)) high(n:S,nil) -> nil if_high(ffalse,n:S,add(m:S,x:S)) -> add(m:S,high(n:S,x:S)) if_high(ttrue,n:S,add(m:S,x:S)) -> high(n:S,x:S) if_low(ffalse,n:S,add(m:S,x:S)) -> low(n:S,x:S) if_low(ttrue,n:S,add(m:S,x:S)) -> add(m:S,low(n:S,x:S)) le(0,y:S) -> ttrue le(s(x:S),0) -> ffalse le(s(x:S),s(y:S)) -> le(x:S,y:S) low(n:S,add(m:S,x:S)) -> if_low(le(m:S,n:S),n:S,add(m:S,x:S)) low(n:S,nil) -> nil minus(s(x:S),s(y:S)) -> minus(x:S,y:S) minus(x:S,0) -> x:S quicksort(add(n:S,x:S)) -> app(quicksort(low(n:S,x:S)),add(n:S,quicksort(high(n:S,x:S)))) quicksort(nil) -> nil quot(0,s(y:S)) -> 0
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