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TRS Standard pair #516967264
details
property
value
status
complete
benchmark
#3.36.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n003.star.cs.uiowa.edu
space
AG01
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
0.525683879852 seconds
cpu usage
0.97351207
max memory
2.00667136E8
stage attributes
key
value
output-size
2483
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: minus(x,0()) -> x minus(s(x),s(y)) -> minus(x,y) f(0()) -> s(0()) f(s(x)) -> minus(s(x),g(f(x))) g(0()) -> 0() g(s(x)) -> minus(s(x),f(g(x))) Proof: Matrix Interpretation Processor: dim=1 interpretation: [g](x0) = 4x0, [minus](x0, x1) = x0 + x1, [f](x0) = 4x0 + 4, [0] = 0, [s](x0) = 6x0 + 4 orientation: minus(x,0()) = x >= x = x minus(s(x),s(y)) = 6x + 6y + 8 >= x + y = minus(x,y) f(0()) = 4 >= 4 = s(0()) f(s(x)) = 24x + 20 >= 22x + 20 = minus(s(x),g(f(x))) g(0()) = 0 >= 0 = 0() g(s(x)) = 24x + 16 >= 22x + 8 = minus(s(x),f(g(x))) problem: minus(x,0()) -> x f(0()) -> s(0()) f(s(x)) -> minus(s(x),g(f(x))) g(0()) -> 0() Matrix Interpretation Processor: dim=1 interpretation: [g](x0) = x0, [minus](x0, x1) = x0 + x1, [f](x0) = 2x0, [0] = 1, [s](x0) = 2x0 orientation: minus(x,0()) = x + 1 >= x = x f(0()) = 2 >= 2 = s(0()) f(s(x)) = 4x >= 4x = minus(s(x),g(f(x))) g(0()) = 1 >= 1 = 0() problem: f(0()) -> s(0()) f(s(x)) -> minus(s(x),g(f(x))) g(0()) -> 0() Matrix Interpretation Processor: dim=1 interpretation: [g](x0) = x0, [minus](x0, x1) = x0 + 2x1 + 2, [f](x0) = 4x0 + 2, [0] = 1, [s](x0) = 4x0 + 2 orientation: f(0()) = 6 >= 6 = s(0()) f(s(x)) = 16x + 10 >= 12x + 8 = minus(s(x),g(f(x))) g(0()) = 1 >= 1 = 0() problem: f(0()) -> s(0()) g(0()) -> 0() Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1] [g](x0) = [0 0 0]x0 + [0] [0 0 0] [0], [1 0 0] [1] [f](x0) = [0 0 0]x0 + [0]
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