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TRS Standard pair #516967709
details
property
value
status
complete
benchmark
#4.22.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n098.star.cs.uiowa.edu
space
Strategy_removed_AG01
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
0.494251012802 seconds
cpu usage
0.674244326
max memory
1.43212544E8
stage attributes
key
value
output-size
1131
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: quot(0(),s(y),s(z)) -> 0() quot(s(x),s(y),z) -> quot(x,y,z) quot(x,0(),s(z)) -> s(quot(x,s(z),s(z))) Proof: DP Processor: DPs: quot#(s(x),s(y),z) -> quot#(x,y,z) quot#(x,0(),s(z)) -> quot#(x,s(z),s(z)) TRS: quot(0(),s(y),s(z)) -> 0() quot(s(x),s(y),z) -> quot(x,y,z) quot(x,0(),s(z)) -> s(quot(x,s(z),s(z))) Subterm Criterion Processor: simple projection: pi(quot#) = 0 problem: DPs: quot#(x,0(),s(z)) -> quot#(x,s(z),s(z)) TRS: quot(0(),s(y),s(z)) -> 0() quot(s(x),s(y),z) -> quot(x,y,z) quot(x,0(),s(z)) -> s(quot(x,s(z),s(z))) EDG Processor: DPs: quot#(x,0(),s(z)) -> quot#(x,s(z),s(z)) TRS: quot(0(),s(y),s(z)) -> 0() quot(s(x),s(y),z) -> quot(x,y,z) quot(x,0(),s(z)) -> s(quot(x,s(z),s(z))) graph: SCC Processor: #sccs: 0 #rules: 0 #arcs: 0/1
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