details

property	value
status	complete
benchmark	isNat.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n177.star.cs.uiowa.edu
space	AProVE_10

run statistics

property	value
solver	AProVE21
configuration	standard
runtime (wallclock)	17.1504290104 seconds
cpu usage	26.39764465
max memory	7.47646976E8

stage attributes

key	value
output-size	7221
starexec-result	NO

output

/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 mhark 20210624 unpublished Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) AAECC Innermost [EQUIVALENT, 0 ms] (2) QTRS (3) DependencyPairsProof [EQUIVALENT, 0 ms] (4) QDP (5) DependencyGraphProof [EQUIVALENT, 0 ms] (6) AND (7) QDP (8) UsableRulesProof [EQUIVALENT, 0 ms] (9) QDP (10) QReductionProof [EQUIVALENT, 0 ms] (11) QDP (12) QDPSizeChangeProof [EQUIVALENT, 0 ms] (13) YES (14) QDP (15) MNOCProof [EQUIVALENT, 0 ms] (16) QDP (17) NonLoopProof [COMPLETE, 0 ms] (18) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(tt, x) -> f(isNat(x), s(x)) isNat(s(x)) -> isNat(x) isNat(0) -> tt Q is empty. ---------------------------------------- (1) AAECC Innermost (EQUIVALENT) We have applied [NOC,AAECCNOC] to switch to innermost. The TRS R 1 is isNat(s(x)) -> isNat(x) isNat(0) -> tt The TRS R 2 is f(tt, x) -> f(isNat(x), s(x)) The signature Sigma is {f_2} ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(tt, x) -> f(isNat(x), s(x)) isNat(s(x)) -> isNat(x) isNat(0) -> tt The set Q consists of the following terms: f(tt, x0) isNat(s(x0)) isNat(0) ---------------------------------------- (3) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (4) Obligation: Q DP problem: The TRS P consists of the following rules: F(tt, x) -> F(isNat(x), s(x)) F(tt, x) -> ISNAT(x) ISNAT(s(x)) -> ISNAT(x) The TRS R consists of the following rules: f(tt, x) -> f(isNat(x), s(x)) isNat(s(x)) -> isNat(x) isNat(0) -> tt The set Q consists of the following terms: f(tt, x0) popout

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all output return to TRS Standard