details

property	value
status	complete
benchmark	t007.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n143.star.cs.uiowa.edu
space	HirokawaMiddeldorp_04

run statistics

property	value
solver	AProVE21
configuration	standard
runtime (wallclock)	2.65271282196 seconds
cpu usage	7.524723118
max memory	6.91638272E8

stage attributes

key	value
output-size	3229
starexec-result	YES

output

/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 mhark 20210624 unpublished Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) FlatCCProof [EQUIVALENT, 0 ms] (2) QTRS (3) RootLabelingProof [EQUIVALENT, 0 ms] (4) QTRS (5) QTRSRRRProof [EQUIVALENT, 4 ms] (6) QTRS (7) RisEmptyProof [EQUIVALENT, 0 ms] (8) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(a) -> f(b) g(b) -> g(a) f(x) -> g(x) Q is empty. ---------------------------------------- (1) FlatCCProof (EQUIVALENT) We used flat context closure [ROOTLAB] As Q is empty the flat context closure was sound AND complete. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(a) -> f(b) g(b) -> g(a) f(f(x)) -> f(g(x)) g(f(x)) -> g(g(x)) Q is empty. ---------------------------------------- (3) RootLabelingProof (EQUIVALENT) We used plain root labeling [ROOTLAB] with the following heuristic: LabelAll: All function symbols get labeled As Q is empty the root labeling was sound AND complete. ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f_{a}(a) -> f_{b}(b) g_{b}(b) -> g_{a}(a) f_{f_1}(f_{f_1}(x)) -> f_{g_1}(g_{f_1}(x)) f_{f_1}(f_{a}(x)) -> f_{g_1}(g_{a}(x)) f_{f_1}(f_{b}(x)) -> f_{g_1}(g_{b}(x)) f_{f_1}(f_{g_1}(x)) -> f_{g_1}(g_{g_1}(x)) g_{f_1}(f_{f_1}(x)) -> g_{g_1}(g_{f_1}(x)) g_{f_1}(f_{a}(x)) -> g_{g_1}(g_{a}(x)) g_{f_1}(f_{b}(x)) -> g_{g_1}(g_{b}(x)) g_{f_1}(f_{g_1}(x)) -> g_{g_1}(g_{g_1}(x)) Q is empty. ---------------------------------------- (5) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(a) = 0 POL(b) = 1 POL(f_{a}(x_1)) = 2 + x_1 POL(f_{b}(x_1)) = x_1 POL(f_{f_1}(x_1)) = 1 + x_1 POL(f_{g_1}(x_1)) = x_1 POL(g_{a}(x_1)) = x_1 POL(g_{b}(x_1)) = x_1 POL(g_{f_1}(x_1)) = 1 + x_1 popout

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all output return to TRS Standard