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SRS Standard pair #516968288
details
property
value
status
complete
benchmark
torpa3.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n098.star.cs.uiowa.edu
space
Secret_05_SRS
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
2.55935192108 seconds
cpu usage
8.640105376
max memory
7.93382912E8
stage attributes
key
value
output-size
8842
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: b(b(x1)) -> c(d(x1)) c(c(x1)) -> d(d(d(x1))) c(x1) -> g(x1) d(d(x1)) -> c(f(x1)) d(d(d(x1))) -> g(c(x1)) f(x1) -> a(g(x1)) g(x1) -> d(a(b(x1))) g(g(x1)) -> b(c(x1)) Proof: Matrix Interpretation Processor: dim=2 interpretation: [1 2] [1] [f](x0) = [0 0]x0 + [0], [1 2] [0] [d](x0) = [0 0]x0 + [1], [1 2] [1] [g](x0) = [0 0]x0 + [1], [1 0] [a](x0) = [0 0]x0, [1 2] [1] [b](x0) = [0 0]x0 + [1], [1 2] [1] [c](x0) = [0 0]x0 + [1] orientation: [1 2] [4] [1 2] [3] b(b(x1)) = [0 0]x1 + [1] >= [0 0]x1 + [1] = c(d(x1)) [1 2] [4] [1 2] [4] c(c(x1)) = [0 0]x1 + [1] >= [0 0]x1 + [1] = d(d(d(x1))) [1 2] [1] [1 2] [1] c(x1) = [0 0]x1 + [1] >= [0 0]x1 + [1] = g(x1) [1 2] [2] [1 2] [2] d(d(x1)) = [0 0]x1 + [1] >= [0 0]x1 + [1] = c(f(x1)) [1 2] [4] [1 2] [4] d(d(d(x1))) = [0 0]x1 + [1] >= [0 0]x1 + [1] = g(c(x1)) [1 2] [1] [1 2] [1] f(x1) = [0 0]x1 + [0] >= [0 0]x1 + [0] = a(g(x1)) [1 2] [1] [1 2] [1] g(x1) = [0 0]x1 + [1] >= [0 0]x1 + [1] = d(a(b(x1))) [1 2] [4] [1 2] [4] g(g(x1)) = [0 0]x1 + [1] >= [0 0]x1 + [1] = b(c(x1)) problem: c(c(x1)) -> d(d(d(x1))) c(x1) -> g(x1) d(d(x1)) -> c(f(x1)) d(d(d(x1))) -> g(c(x1)) f(x1) -> a(g(x1)) g(x1) -> d(a(b(x1))) g(g(x1)) -> b(c(x1)) String Reversal Processor: c(c(x1)) -> d(d(d(x1))) c(x1) -> g(x1) d(d(x1)) -> f(c(x1)) d(d(d(x1))) -> c(g(x1)) f(x1) -> g(a(x1)) g(x1) -> b(a(d(x1))) g(g(x1)) -> c(b(x1)) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [0] [f](x0) = [0 0 0]x0 + [1] [0 0 0] [0], [1 1 0] [0] [d](x0) = [0 0 1]x0 + [0] [0 0 0] [1], [1 1 0] [0] [g](x0) = [0 0 0]x0 + [1] [0 0 0] [0], [1 0 0] [0] [a](x0) = [0 0 0]x0 + [0] [0 0 0] [1], [1 1 0] [b](x0) = [0 0 0]x0
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