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SRS Standard pair #516968369
details
property
value
status
complete
benchmark
z094.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n098.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
MnM 3.18b
configuration
default
runtime (wallclock)
0.966694116592 seconds
cpu usage
2.167276959
max memory
5.70249216E8
stage attributes
key
value
output-size
4395
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES After renaming modulo the bijection { f ↦ 0, n ↦ 1, c ↦ 2, s ↦ 3 }, it remains to prove termination of the 5-rule system { 0 ⟶ 1 2 2 , 2 0 ⟶ 0 2 2 , 2 2 ⟶ 2 , 1 3 ⟶ 0 3 3 , 1 0 ⟶ 0 1 } Applying the dependency pairs transformation. Here, ↑ marks so-called defined symbols. After renaming modulo the bijection { (0,↑) ↦ 0, (1,↑) ↦ 1, (2,↓) ↦ 2, (2,↑) ↦ 3, (0,↓) ↦ 4, (3,↓) ↦ 5, (1,↓) ↦ 6 }, it remains to prove termination of the 14-rule system { 0 ⟶ 1 2 2 , 0 ⟶ 3 2 , 0 ⟶ 3 , 3 4 ⟶ 0 2 2 , 3 4 ⟶ 3 2 , 3 4 ⟶ 3 , 1 5 ⟶ 0 5 5 , 1 4 ⟶ 0 6 , 1 4 ⟶ 1 , 4 →= 6 2 2 , 2 4 →= 4 2 2 , 2 2 →= 2 , 6 5 →= 4 5 5 , 6 4 →= 4 6 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 ↦ ⎛ ⎞ ⎜ 1 1 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 1 ↦ ⎛ ⎞ ⎜ 1 1 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 2 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 3 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 4 ↦ ⎛ ⎞ ⎜ 1 2 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 5 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 6 ↦ ⎛ ⎞ ⎜ 1 2 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ After renaming modulo the bijection { 0 ↦ 0, 1 ↦ 1, 2 ↦ 2, 5 ↦ 3, 4 ↦ 4, 6 ↦ 5 }, it remains to prove termination of the 8-rule system { 0 ⟶ 1 2 2 , 1 3 ⟶ 0 3 3 , 1 4 ⟶ 0 5 , 4 →= 5 2 2 , 2 4 →= 4 2 2 , 2 2 →= 2 , 5 3 →= 4 3 3 , 5 4 →= 4 5 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 3: 0 ↦ ⎛ ⎞ ⎜ 1 0 0 ⎟ ⎜ 0 1 0 ⎟ ⎜ 0 0 0 ⎟ ⎝ ⎠ 1 ↦ ⎛ ⎞ ⎜ 1 0 1 ⎟ ⎜ 0 1 0 ⎟ ⎜ 0 0 0 ⎟ ⎝ ⎠ 2 ↦ ⎛ ⎞
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