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SRS Standard pair #516968381
details
property
value
status
complete
benchmark
z113.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n090.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
MnM 3.18b
configuration
default
runtime (wallclock)
1.06649112701 seconds
cpu usage
2.341228572
max memory
7.43972864E8
stage attributes
key
value
output-size
2760
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES After renaming modulo the bijection { 1 ↦ 0, 4 ↦ 1, 3 ↦ 2, 2 ↦ 3, 5 ↦ 4, 6 ↦ 5 }, it remains to prove termination of the 9-rule system { 0 0 ⟶ 1 2 , 0 3 ⟶ 3 0 , 3 3 ⟶ 0 0 0 , 2 2 ⟶ 4 5 , 2 1 ⟶ 0 0 , 1 1 ⟶ 2 , 4 4 ⟶ 5 3 , 4 5 ⟶ 0 3 , 5 5 ⟶ 3 0 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 ↦ ⎛ ⎞ ⎜ 1 85 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 1 ↦ ⎛ ⎞ ⎜ 1 57 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 2 ↦ ⎛ ⎞ ⎜ 1 113 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 3 ↦ ⎛ ⎞ ⎜ 1 128 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 4 ↦ ⎛ ⎞ ⎜ 1 118 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 5 ↦ ⎛ ⎞ ⎜ 1 107 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ After renaming modulo the bijection { 0 ↦ 0, 1 ↦ 1, 2 ↦ 2, 3 ↦ 3 }, it remains to prove termination of the 3-rule system { 0 0 ⟶ 1 2 , 0 3 ⟶ 3 0 , 2 1 ⟶ 0 0 } Applying sparse untiling TRFCU(2) after reversal [Geser/Hofbauer/Waldmann, FSCD 2019]. After renaming modulo the bijection { 0 ↦ 0, 2 ↦ 1, 1 ↦ 2 }, it remains to prove termination of the 2-rule system { 0 0 ⟶ 1 2 , 2 1 ⟶ 0 0 } Applying the dependency pairs transformation. Here, ↑ marks so-called defined symbols. After renaming modulo the bijection { (0,↑) ↦ 0, (0,↓) ↦ 1, (2,↑) ↦ 2, (1,↓) ↦ 3, (2,↓) ↦ 4 }, it remains to prove termination of the 5-rule system { 0 1 ⟶ 2 , 2 3 ⟶ 0 1 , 2 3 ⟶ 0 , 1 1 →= 3 4 , 4 3 →= 1 1 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 ↦ ⎛ ⎞ ⎜ 1 1 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 1 ↦ ⎛ ⎞ ⎜ 1 1 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 2 ↦ ⎛ ⎞ ⎜ 1 1 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 3 ↦ ⎛ ⎞ ⎜ 1 1 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 4 ↦ ⎛ ⎞
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