details

property	value
status	complete
benchmark	z114.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n082.star.cs.uiowa.edu
space	Zantema_04

run statistics

property	value
solver	MnM 3.18b
configuration	default
runtime (wallclock)	2.26702904701 seconds
cpu usage	7.220711603
max memory	1.188491264E9

stage attributes

key	value
output-size	3587
starexec-result	YES

output

/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES After renaming modulo the bijection { a ↦ 0, c ↦ 1, b ↦ 2 }, it remains to prove termination of the 3-rule system { 0 1 ⟶ 1 2 , 0 ⟶ 2 2 2 , 2 1 2 ⟶ 0 1 } The system was reversed. After renaming modulo the bijection { 1 ↦ 0, 0 ↦ 1, 2 ↦ 2 }, it remains to prove termination of the 3-rule system { 0 1 ⟶ 2 0 , 1 ⟶ 2 2 2 , 2 0 2 ⟶ 0 1 } Applying the dependency pairs transformation. Here, ↑ marks so-called defined symbols. After renaming modulo the bijection { (0,↑) ↦ 0, (1,↓) ↦ 1, (2,↑) ↦ 2, (0,↓) ↦ 3, (1,↑) ↦ 4, (2,↓) ↦ 5 }, it remains to prove termination of the 10-rule system { 0 1 ⟶ 2 3 , 0 1 ⟶ 0 , 4 ⟶ 2 5 5 , 4 ⟶ 2 5 , 4 ⟶ 2 , 2 3 5 ⟶ 0 1 , 2 3 5 ⟶ 4 , 3 1 →= 5 3 , 1 →= 5 5 5 , 5 3 5 →= 3 1 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 ↦ ⎛ ⎞ ⎜ 1 2 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 1 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 2 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 3 ↦ ⎛ ⎞ ⎜ 1 2 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 4 ↦ ⎛ ⎞ ⎜ 1 1 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 5 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ After renaming modulo the bijection { 0 ↦ 0, 1 ↦ 1, 2 ↦ 2, 3 ↦ 3, 5 ↦ 4 }, it remains to prove termination of the 6-rule system { 0 1 ⟶ 2 3 , 0 1 ⟶ 0 , 2 3 4 ⟶ 0 1 , 3 1 →= 4 3 , 1 →= 4 4 4 , 4 3 4 →= 3 1 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 3: 0 ↦ ⎛ ⎞ ⎜ 1 0 1 ⎟ ⎜ 0 1 0 ⎟ ⎜ 0 0 0 ⎟ ⎝ ⎠ 1 ↦ ⎛ ⎞ ⎜ 1 0 0 ⎟ ⎜ 0 1 1 ⎟ ⎜ 0 1 1 ⎟ ⎝ ⎠ 2 ↦ ⎛ ⎞ ⎜ 1 1 0 ⎟ ⎜ 0 1 0 ⎟ ⎜ 0 0 0 ⎟ ⎝ ⎠ popout

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