Spaces
Explore
Communities
Statistics
Reports
Cluster
Status
Help
SRS Standard pair #516968621
details
property
value
status
complete
benchmark
z083.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n146.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
MnM 3.18b
configuration
default
runtime (wallclock)
1.40972995758 seconds
cpu usage
3.725894694
max memory
1.052123136E9
stage attributes
key
value
output-size
7689
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES After renaming modulo the bijection { b ↦ 0, d ↦ 1, c ↦ 2, a ↦ 3 }, it remains to prove termination of the 7-rule system { 0 1 0 ⟶ 2 1 0 , 0 3 2 ⟶ 0 2 , 3 1 ⟶ 1 2 , 0 0 0 ⟶ 3 0 2 , 1 2 ⟶ 0 1 , 1 2 ⟶ 1 0 1 , 1 3 2 ⟶ 0 0 } The system was reversed. After renaming modulo the bijection { 0 ↦ 0, 1 ↦ 1, 2 ↦ 2, 3 ↦ 3 }, it remains to prove termination of the 7-rule system { 0 1 0 ⟶ 0 1 2 , 2 3 0 ⟶ 2 0 , 1 3 ⟶ 2 1 , 0 0 0 ⟶ 2 0 3 , 2 1 ⟶ 1 0 , 2 1 ⟶ 1 0 1 , 2 3 1 ⟶ 0 0 } Applying sparse untiling TRFCU(2) [Geser/Hofbauer/Waldmann, FSCD 2019]. After renaming modulo the bijection { 0 ↦ 0, 1 ↦ 1, 2 ↦ 2, 3 ↦ 3 }, it remains to prove termination of the 6-rule system { 0 1 0 ⟶ 0 1 2 , 2 3 0 ⟶ 2 0 , 0 0 0 ⟶ 2 0 3 , 2 1 ⟶ 1 0 , 2 1 ⟶ 1 0 1 , 2 3 1 ⟶ 0 0 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 ↦ ⎛ ⎞ ⎜ 1 1 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 1 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 2 ↦ ⎛ ⎞ ⎜ 1 1 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 3 ↦ ⎛ ⎞ ⎜ 1 1 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ After renaming modulo the bijection { 0 ↦ 0, 1 ↦ 1, 2 ↦ 2, 3 ↦ 3 }, it remains to prove termination of the 5-rule system { 0 1 0 ⟶ 0 1 2 , 0 0 0 ⟶ 2 0 3 , 2 1 ⟶ 1 0 , 2 1 ⟶ 1 0 1 , 2 3 1 ⟶ 0 0 } Applying the dependency pairs transformation. Here, ↑ marks so-called defined symbols. After renaming modulo the bijection { (0,↑) ↦ 0, (1,↓) ↦ 1, (0,↓) ↦ 2, (2,↓) ↦ 3, (2,↑) ↦ 4, (3,↓) ↦ 5 }, it remains to prove termination of the 13-rule system { 0 1 2 ⟶ 0 1 3 , 0 1 2 ⟶ 4 , 0 2 2 ⟶ 4 2 5 , 0 2 2 ⟶ 0 5 , 4 1 ⟶ 0 , 4 1 ⟶ 0 1 , 4 5 1 ⟶ 0 2 , 4 5 1 ⟶ 0 , 2 1 2 →= 2 1 3 , 2 2 2 →= 3 2 5 , 3 1 →= 1 2 , 3 1 →= 1 2 1 , 3 5 1 →= 2 2 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 1 ↦ ⎛ ⎞ ⎜ 1 0 ⎟
popout
output may be truncated. 'popout' for the full output.
job log
popout
actions
all output
return to SRS Standard