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SRS Standard pair #516968738
details
property
value
status
complete
benchmark
z089.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n086.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
1.20850586891 seconds
cpu usage
3.74664901
max memory
7.24344832E8
stage attributes
key
value
output-size
2026
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: a(b(b(a(x1)))) -> a(c(a(b(x1)))) a(c(x1)) -> c(c(a(x1))) c(c(c(x1))) -> b(c(b(x1))) Proof: String Reversal Processor: a(b(b(a(x1)))) -> b(a(c(a(x1)))) c(a(x1)) -> a(c(c(x1))) c(c(c(x1))) -> b(c(b(x1))) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [b](x0) = [0 1 1]x0 [0 0 0] , [1 1 0] [0] [a](x0) = [0 1 0]x0 + [0] [0 0 0] [1], [1 0 0] [c](x0) = [0 0 0]x0 [0 0 1] orientation: [1 2 0] [1] [1 1 0] [0] a(b(b(a(x1)))) = [0 1 0]x1 + [1] >= [0 0 0]x1 + [1] = b(a(c(a(x1)))) [0 0 0] [1] [0 0 0] [0] [1 1 0] [0] [1 0 0] [0] c(a(x1)) = [0 0 0]x1 + [0] >= [0 0 0]x1 + [0] = a(c(c(x1))) [0 0 0] [1] [0 0 0] [1] [1 0 0] [1 0 0] c(c(c(x1))) = [0 0 0]x1 >= [0 0 0]x1 = b(c(b(x1))) [0 0 1] [0 0 0] problem: c(a(x1)) -> a(c(c(x1))) c(c(c(x1))) -> b(c(b(x1))) String Reversal Processor: a(c(x1)) -> c(c(a(x1))) c(c(c(x1))) -> b(c(b(x1))) Bounds Processor: bound: 1 enrichment: match automaton: final states: {5,1} transitions: a0(2) -> 3* b1(16) -> 17* b1(12) -> 13* b1(14) -> 15* b1(18) -> 19* b0(2) -> 6* b0(7) -> 5* c0(3) -> 4* c0(4) -> 1* c0(6) -> 7* f30() -> 2* c1(17) -> 18* c1(13) -> 14* 19 -> 4* 4 -> 12* 1 -> 3* 3 -> 16* 15 -> 1* problem: Qed
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