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SRS Standard pair #516968746
details
property
value
status
complete
benchmark
z058.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n083.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
AProVE21
configuration
standard
runtime (wallclock)
3.95000910759 seconds
cpu usage
6.482829594
max memory
6.83073536E8
stage attributes
key
value
output-size
2148
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 mhark 20210624 unpublished Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (4) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: b(a(b(a(b(b(x1)))))) -> a(b(b(a(b(b(a(x1))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: b(b(a(b(a(b(x1)))))) -> a(b(b(a(b(b(a(x1))))))) Q is empty. ---------------------------------------- (3) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: b(b(a(b(a(b(x1)))))) -> a(b(b(a(b(b(a(x1))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52 Node 39 is start node and node 40 is final node. Those nodes are connected through the following edges: * 39 to 41 labelled a_1(0)* 40 to 40 labelled #_1(0)* 41 to 42 labelled b_1(0)* 42 to 43 labelled b_1(0)* 43 to 44 labelled a_1(0)* 44 to 45 labelled b_1(0)* 44 to 47 labelled a_1(1)* 45 to 46 labelled b_1(0)* 46 to 40 labelled a_1(0)* 47 to 48 labelled b_1(1)* 48 to 49 labelled b_1(1)* 49 to 50 labelled a_1(1)* 50 to 51 labelled b_1(1)* 50 to 47 labelled a_1(1)* 51 to 52 labelled b_1(1)* 52 to 40 labelled a_1(1) ---------------------------------------- (4) YES
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