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SRS Standard pair #516968936
details
property
value
status
complete
benchmark
z019.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n115.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
0.889498949051 seconds
cpu usage
2.2995523
max memory
6.35150336E8
stage attributes
key
value
output-size
1575
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: a(b(x1)) -> b(c(a(x1))) b(c(x1)) -> c(b(b(x1))) c(a(x1)) -> a(c(x1)) Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 1 0] [a](x0) = [0 1 0]x0 [0 0 0] , [1 0 0] [0] [b](x0) = [0 1 0]x0 + [1] [0 0 0] [0], [1 0 0] [c](x0) = [0 0 0]x0 [0 0 0] orientation: [1 1 0] [1] [1 1 0] [0] a(b(x1)) = [0 1 0]x1 + [1] >= [0 0 0]x1 + [1] = b(c(a(x1))) [0 0 0] [0] [0 0 0] [0] [1 0 0] [0] [1 0 0] b(c(x1)) = [0 0 0]x1 + [1] >= [0 0 0]x1 = c(b(b(x1))) [0 0 0] [0] [0 0 0] [1 1 0] [1 0 0] c(a(x1)) = [0 0 0]x1 >= [0 0 0]x1 = a(c(x1)) [0 0 0] [0 0 0] problem: b(c(x1)) -> c(b(b(x1))) c(a(x1)) -> a(c(x1)) String Reversal Processor: c(b(x1)) -> b(b(c(x1))) a(c(x1)) -> c(a(x1)) Bounds Processor: bound: 0 enrichment: match automaton: final states: {5,1} transitions: c0(2) -> 3* c0(6) -> 5* f30() -> 2* b0(3) -> 4* b0(4) -> 1* a0(2) -> 6* 1 -> 3* 5 -> 6* problem: Qed
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