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SRS Standard pair #516969128
details
property
value
status
complete
benchmark
pi.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n065.star.cs.uiowa.edu
space
Waldmann_06_SRS
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
4.16074204445 seconds
cpu usage
15.128738509
max memory
1.155239936E9
stage attributes
key
value
output-size
7440
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: 3(1(x1)) -> 4(1(x1)) 5(9(x1)) -> 2(6(5(x1))) 3(5(x1)) -> 8(9(7(x1))) 9(x1) -> 3(2(3(x1))) 8(4(x1)) -> 6(x1) 2(6(x1)) -> 4(3(x1)) 3(8(x1)) -> 3(2(7(x1))) 9(x1) -> 5(0(2(x1))) 8(8(4(x1))) -> 1(9(x1)) 7(1(x1)) -> 6(9(x1)) 3(9(x1)) -> 9(3(x1)) 7(5(x1)) -> 1(0(x1)) Proof: String Reversal Processor: 1(3(x1)) -> 1(4(x1)) 9(5(x1)) -> 5(6(2(x1))) 5(3(x1)) -> 7(9(8(x1))) 9(x1) -> 3(2(3(x1))) 4(8(x1)) -> 6(x1) 6(2(x1)) -> 3(4(x1)) 8(3(x1)) -> 7(2(3(x1))) 9(x1) -> 2(0(5(x1))) 4(8(8(x1))) -> 9(1(x1)) 1(7(x1)) -> 9(6(x1)) 9(3(x1)) -> 3(9(x1)) 5(7(x1)) -> 0(1(x1)) Matrix Interpretation Processor: dim=3 interpretation: [1 0 1] [5](x0) = [0 0 0]x0 [0 1 0] , [1 1 0] [0] [8](x0) = [1 1 0]x0 + [1] [0 0 1] [0], [1 0 0] [3](x0) = [0 0 1]x0 [0 1 1] , [1 0 1] [9](x0) = [0 0 0]x0 [0 0 0] , [1 0 0] [6](x0) = [0 0 0]x0 [0 0 0] , [1 0 0] [1](x0) = [0 0 1]x0 [0 0 0] , [1 0 0] [7](x0) = [0 0 0]x0 [0 0 1] , [1 1 0] [0](x0) = [0 0 0]x0 [0 0 0] , [1 1 0] [2](x0) = [0 0 0]x0 [0 0 0] , [1 0 0] [4](x0) = [0 0 0]x0 [0 0 0] orientation: [1 0 0] [1 0 0] 1(3(x1)) = [0 1 1]x1 >= [0 0 0]x1 = 1(4(x1)) [0 0 0] [0 0 0] [1 1 1] [1 1 0] 9(5(x1)) = [0 0 0]x1 >= [0 0 0]x1 = 5(6(2(x1))) [0 0 0] [0 0 0] [1 1 1] [1 1 1] 5(3(x1)) = [0 0 0]x1 >= [0 0 0]x1 = 7(9(8(x1))) [0 0 1] [0 0 0] [1 0 1] [1 0 1] 9(x1) = [0 0 0]x1 >= [0 0 0]x1 = 3(2(3(x1))) [0 0 0] [0 0 0] [1 1 0] [1 0 0] 4(8(x1)) = [0 0 0]x1 >= [0 0 0]x1 = 6(x1) [0 0 0] [0 0 0] [1 1 0] [1 0 0]
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