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SRS Standard pair #516969184
details
property
value
status
complete
benchmark
1.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n089.star.cs.uiowa.edu
space
Mixed_SRS
run statistics
property
value
solver
AProVE21
configuration
standard
runtime (wallclock)
2.36780786514 seconds
cpu usage
6.20028364
max memory
5.9506688E8
stage attributes
key
value
output-size
1861
starexec-result
NO
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 mhark 20210624 unpublished Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) NonTerminationProof [COMPLETE, 140 ms] (2) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: b(c(x1)) -> a(b(b(x1))) b(a(x1)) -> a(c(b(x1))) Q is empty. ---------------------------------------- (1) NonTerminationProof (COMPLETE) We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite. Found the self-embedding DerivationStructure: "b c a a c a -> a a c a b a c b c a a c a b b b" b c a a c a -> a a c a b a c b c a a c a b b b by OverlapClosure OC 2"b c a a -> a a c a b a c b c b by OverlapClosure OC 3"b c a a -> a a c a b b a c b by OverlapClosure OC 2"b c a -> a a c a b b b by OverlapClosure OC 3"b c a -> a a c b c b by OverlapClosure OC 3"b c a -> a b a c b by OverlapClosure OC 2"b c -> a b b by original rule (OC 1)""b a -> a c b by original rule (OC 1)"""b a -> a c b by original rule (OC 1)"""b c -> a b b by original rule (OC 1)"""b a -> a c b by original rule (OC 1)"""b a -> a c b by original rule (OC 1)"""b c a -> a a c a b b b by OverlapClosure OC 3"b c a -> a a c b c b by OverlapClosure OC 3"b c a -> a b a c b by OverlapClosure OC 2"b c -> a b b by original rule (OC 1)""b a -> a c b by original rule (OC 1)"""b a -> a c b by original rule (OC 1)"""b c -> a b b by original rule (OC 1)"" ---------------------------------------- (2) NO
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