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SRS Standard pair #516973241
details
property
value
status
complete
benchmark
num-521.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n009.star.cs.uiowa.edu
space
Secret_07_SRS
run statistics
property
value
solver
MnM 3.18b
configuration
default
runtime (wallclock)
0.610641002655 seconds
cpu usage
0.911737009
max memory
4.4029952E8
stage attributes
key
value
output-size
1523
starexec-result
NO
output
/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- NO After renaming modulo the bijection { a ↦ 0, b ↦ 1, c ↦ 2 }, it remains to prove termination of the 2-rule system { 0 0 1 ⟶ 0 1 2 0 0 , 0 2 ⟶ 1 0 } The system was reversed. After renaming modulo the bijection { 1 ↦ 0, 0 ↦ 1, 2 ↦ 2 }, it remains to prove termination of the 2-rule system { 0 1 1 ⟶ 1 1 2 0 1 , 2 1 ⟶ 1 0 } Loop of length 16 starting with a string of length 7 using right expansion and the encoding { 0 ↦ a, 1 ↦ b, ... }: .abb.bbbb rule abb-> bbcab at position 0 .bbcab.bbbb rule abb-> bbcab at position 3 .bbcbbcab.bbb rule cb-> ba at position 2 .bbbabcab.bbb rule abb-> bbcab at position 6 .bbbabcbbcab.bb rule cb-> ba at position 5 .bbbabbabcab.bb rule abb-> bbcab at position 9 .bbbabbabcbbcab.b rule cb-> ba at position 8 .bbbabbabbabcab.b rule abb-> bbcab at position 6 .bbbabbbbcababcab.b rule abb-> bbcab at position 14 .bbbabbbbcababcbbcab. rule cb-> ba at position 13 .bbbabbbbcababbabcab. rule abb-> bbcab at position 11 .bbbabbbbcabbbcababcab. rule abb-> bbcab at position 9 .bbbabbbbcbbcabbcababcab. rule cb-> ba at position 8 .bbbabbbbbabcabbcababcab. rule abb-> bbcab at position 12 .bbbabbbbbabcbbcabcababcab. rule cb-> ba at position 11 .bbbabbbbbabbabcabcababcab. rule abb-> bbcab at position 9 .bbbabbbbbbbcababcabcababcab.
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