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SRS Standard pair #516973247
details
property
value
status
complete
benchmark
num-530.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n169.star.cs.uiowa.edu
space
Secret_07_SRS
run statistics
property
value
solver
MnM 3.18b
configuration
default
runtime (wallclock)
0.564501047134 seconds
cpu usage
0.794061885
max memory
4.2504192E8
stage attributes
key
value
output-size
1212
starexec-result
NO
output
/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- NO After renaming modulo the bijection { a ↦ 0, b ↦ 1, c ↦ 2 }, it remains to prove termination of the 2-rule system { 0 0 1 ⟶ 1 2 1 0 0 0 , 0 2 ⟶ 1 } Loop of length 12 starting with a string of length 8 using right expansion and the encoding { 0 ↦ a, 1 ↦ b, ... }: .aab.babcb rule aab-> bcbaaa at position 0 .bcbaaa.babcb rule aab-> bcbaaa at position 4 .bcbabcbaaa.abcb rule aab-> bcbaaa at position 9 .bcbabcbaabcbaaa.cb rule aab-> bcbaaa at position 7 .bcbabcbbcbaaacbaaa.cb rule ac-> b at position 12 .bcbabcbbcbaabbaaa.cb rule aab-> bcbaaa at position 10 .bcbabcbbcbbcbaaabaaa.cb rule aab-> bcbaaa at position 14 .bcbabcbbcbbcbabcbaaaaaa.cb rule ac-> b at position 22 .bcbabcbbcbbcbabcbaaaaab.b rule aab-> bcbaaa at position 20 .bcbabcbbcbbcbabcbaaabcbaaa.b rule aab-> bcbaaa at position 18 .bcbabcbbcbbcbabcbabcbaaacbaaa.b rule ac-> b at position 23 .bcbabcbbcbbcbabcbabcbaabbaaa.b rule aab-> bcbaaa at position 26 .bcbabcbbcbbcbabcbabcbaabbabcbaaa.
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