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SRS Standard pair #516973745
details
property
value
status
complete
benchmark
size-12-alpha-3-num-383.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n081.star.cs.uiowa.edu
space
Waldmann_07_size12
run statistics
property
value
solver
MnM 3.18b
configuration
default
runtime (wallclock)
6.261054039 seconds
cpu usage
23.051545733
max memory
3.849183232E9
stage attributes
key
value
output-size
1358
starexec-result
NO
output
/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- NO After renaming modulo the bijection { a ↦ 0, b ↦ 1, c ↦ 2 }, it remains to prove termination of the 2-rule system { 0 ⟶ 1 , 1 0 0 2 ⟶ 2 2 0 0 0 0 } Loop of length 16 starting with a string of length 11 using right expansion and the encoding { 0 ↦ a, 1 ↦ b, ... }: .a.aacaaccacc rule a-> b at position 0 .b.aacaaccacc rule baac-> ccaaaa at position 0 .ccaaaa.aaccacc rule a-> b at position 2 .ccbaaa.aaccacc rule a-> b at position 5 .ccbaab.aaccacc rule baac-> ccaaaa at position 5 .ccbaaccaaaa.cacc rule baac-> ccaaaa at position 2 .ccccaaaacaaaa.cacc rule a-> b at position 5 .ccccabaacaaaa.cacc rule baac-> ccaaaa at position 5 .ccccaccaaaaaaaa.cacc rule a-> b at position 9 .ccccaccaabaaaaa.cacc rule a-> b at position 12 .ccccaccaabaabaa.cacc rule baac-> ccaaaa at position 12 .ccccaccaabaaccaaaa.acc rule baac-> ccaaaa at position 9 .ccccaccaaccaaaacaaaa.acc rule a-> b at position 18 .ccccaccaaccaaaacaaba.acc rule baac-> ccaaaa at position 18 .ccccaccaaccaaaacaaccaaaa.c rule a-> b at position 21 .ccccaccaaccaaaacaaccabaa.c rule baac-> ccaaaa at position 21 .ccccaccaaccaaaacaaccaccaaaa.
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