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SRS Standard pair #516974129
details
property
value
status
complete
benchmark
size-12-alpha-3-num-474.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n146.star.cs.uiowa.edu
space
Waldmann_07_size12
run statistics
property
value
solver
MnM 3.18b
configuration
default
runtime (wallclock)
0.908532142639 seconds
cpu usage
2.062768841
max memory
5.88193792E8
stage attributes
key
value
output-size
1360
starexec-result
NO
output
/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- NO After renaming modulo the bijection { a ↦ 0, b ↦ 1, c ↦ 2 }, it remains to prove termination of the 2-rule system { 0 0 ⟶ 0 1 , 1 0 2 ⟶ 2 2 0 0 0 } Loop of length 16 starting with a string of length 11 using right expansion and the encoding { 0 ↦ a, 1 ↦ b, ... }: .aa.acaaccacc rule aa-> ab at position 0 .ab.acaaccacc rule bac-> ccaaa at position 1 .accaaa.aaccacc rule aa-> ab at position 3 .accaba.aaccacc rule aa-> ab at position 5 .accabab.accacc rule bac-> ccaaa at position 6 .accabaccaaa.cacc rule bac-> ccaaa at position 4 .accaccaaacaaa.cacc rule aa-> ab at position 6 .accaccabacaaa.cacc rule bac-> ccaaa at position 7 .accaccaccaaaaaa.cacc rule aa-> ab at position 10 .accaccaccaabaaa.cacc rule aa-> ab at position 12 .accaccaccaababa.cacc rule bac-> ccaaa at position 13 .accaccaccaabaccaaa.acc rule bac-> ccaaa at position 11 .accaccaccaaccaaacaaa.acc rule aa-> ab at position 18 .accaccaccaaccaaacaab.acc rule bac-> ccaaa at position 19 .accaccaccaaccaaacaaccaaa.c rule aa-> ab at position 21 .accaccaccaaccaaacaaccaba.c rule bac-> ccaaa at position 22 .accaccaccaaccaaacaaccaccaaa.
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