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SRS Standard pair #516974207
details
property
value
status
complete
benchmark
size-12-alpha-3-num-47.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n143.star.cs.uiowa.edu
space
Waldmann_07_size12
run statistics
property
value
solver
MnM 3.18b
configuration
default
runtime (wallclock)
0.559139966965 seconds
cpu usage
0.907930548
max memory
4.30137344E8
stage attributes
key
value
output-size
1202
starexec-result
NO
output
/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- NO After renaming modulo the bijection { a ↦ 0, b ↦ 1, c ↦ 2 }, it remains to prove termination of the 3-rule system { 0 ⟶ , 0 ⟶ 1 2 , 2 1 1 1 ⟶ 1 0 1 0 } Loop of length 15 starting with a string of length 10 using right expansion and the encoding { 0 ↦ a, 1 ↦ b, ... }: .a.bbbbbbbbb rule a-> bc at position 0 .bc.bbbbbbbbb rule cbbb-> baba at position 1 .bbaba.bbbbbb rule a-> bc at position 4 .bbabbc.bbbbbb rule cbbb-> baba at position 5 .bbabbbaba.bbb rule a-> bc at position 6 .bbabbbbcba.bbb rule a-> bc at position 9 .bbabbbbcbbc.bbb rule cbbb-> baba at position 10 .bbabbbbcbbbaba. rule cbbb-> baba at position 7 .bbabbbbbabaaba. rule a-> bc at position 8 .bbabbbbbbcbaaba. rule a-> at position 11 .bbabbbbbbcbaba. rule a-> at position 11 .bbabbbbbbcbba. rule a-> bc at position 12 .bbabbbbbbcbbbc. rule cbbb-> baba at position 9 .bbabbbbbbbabac. rule a-> at position 10 .bbabbbbbbbbac. rule a-> bc at position 11 .bbabbbbbbbbbcc.
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