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SRS Standard pair #516974225
details
property
value
status
complete
benchmark
size-12-alpha-2-num-20.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n139.star.cs.uiowa.edu
space
Waldmann_07_size12
run statistics
property
value
solver
MnM 3.18b
configuration
default
runtime (wallclock)
1.67428517342 seconds
cpu usage
5.168417198
max memory
9.3581312E8
stage attributes
key
value
output-size
1366
starexec-result
NO
output
/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO After renaming modulo the bijection { a ↦ 0, b ↦ 1 }, it remains to prove termination of the 3-rule system { 0 ⟶ , 0 0 1 ⟶ 1 0 1 0 , 1 1 1 ⟶ 0 } The system was reversed. After renaming modulo the bijection { 0 ↦ 0, 1 ↦ 1 }, it remains to prove termination of the 3-rule system { 0 ⟶ , 1 0 0 ⟶ 0 1 0 1 , 1 1 1 ⟶ 0 } Loop of length 14 starting with a string of length 11 using right expansion and the encoding { 0 ↦ a, 1 ↦ b, ... }: .baa.aaaabbaa rule baa-> abab at position 0 .abab.aaaabbaa rule baa-> abab at position 3 .abaabab.aabbaa rule baa-> abab at position 6 .abaabaabab.bbaa rule baa-> abab at position 4 .abaaababbab.bbaa rule bbb-> a at position 10 .abaaababbaa.aa rule baa-> abab at position 8 .abaaabababab.aa rule baa-> abab at position 11 .abaaabababaabab. rule baa-> abab at position 9 .abaaababaababbab. rule baa-> abab at position 7 .abaaabaababbabbab. rule baa-> abab at position 5 .abaaaababbabbabbab. rule a-> at position 7 .abaaaabbbabbabbab. rule bbb-> a at position 6 .abaaaaaabbabbab. rule a-> at position 13 .abaaaaaabbabbb. rule bbb-> a at position 11 .abaaaaaabbaa.
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