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SRS Standard pair #516974440
details
property
value
status
complete
benchmark
size-12-alpha-3-num-353.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n054.star.cs.uiowa.edu
space
Waldmann_07_size12
run statistics
property
value
solver
AProVE21
configuration
standard
runtime (wallclock)
2.23696494102 seconds
cpu usage
6.15014363
max memory
5.63986432E8
stage attributes
key
value
output-size
2023
starexec-result
NO
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 mhark 20210624 unpublished Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) NonTerminationProof [COMPLETE, 123 ms] (2) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(x1) -> b(x1) a(b(x1)) -> b(b(a(c(c(a(x1)))))) c(b(x1)) -> x1 Q is empty. ---------------------------------------- (1) NonTerminationProof (COMPLETE) We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite. Found the self-embedding DerivationStructure: "a b b b -> b b a b b b c c b c c b" a b b b -> b b a b b b c c b c c b by OverlapClosure OC 3"a b b b -> b b a a b c c b by OverlapClosure OC 3"a b b b -> b b a a c b b c c b by OverlapClosure OC 3"a b b b -> b b a a c c b b b c c b by OverlapClosure OC 2"a b b -> b b a a c c a by OverlapClosure OC 3"a b b -> b b a c b a c c a by OverlapClosure OC 3"a b b -> b b a c c b b a c c a by OverlapClosure OC 2"a b -> b b a c c a by original rule (OC 1)""a b -> b b a c c a by original rule (OC 1)"""c b -> by original rule (OC 1)"""c b -> by original rule (OC 1)"""a b -> b b b c c b by OverlapClosure OC 3"a b -> b b a c c b by OverlapClosure OC 2"a b -> b b a c c a by original rule (OC 1)""a -> b by original rule (OC 1)"""a -> b by original rule (OC 1)""""c b -> by original rule (OC 1)"""c b -> by original rule (OC 1)"""a b -> b b b c c b by OverlapClosure OC 3"a b -> b b a c c b by OverlapClosure OC 2"a b -> b b a c c a by original rule (OC 1)""a -> b by original rule (OC 1)"""a -> b by original rule (OC 1)"" ---------------------------------------- (2) NO
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