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SRS Standard pair #516974470
details
property
value
status
complete
benchmark
size-12-alpha-3-num-328.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n060.star.cs.uiowa.edu
space
Waldmann_07_size12
run statistics
property
value
solver
AProVE21
configuration
standard
runtime (wallclock)
5.7824139595 seconds
cpu usage
19.517165177
max memory
1.35571456E9
stage attributes
key
value
output-size
2127
starexec-result
NO
output
/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- NO proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 mhark 20210624 unpublished Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) NonTerminationProof [COMPLETE, 951 ms] (2) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(x1) -> b(x1) a(x1) -> b(b(c(x1))) c(a(b(x1))) -> a(c(a(x1))) Q is empty. ---------------------------------------- (1) NonTerminationProof (COMPLETE) We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite. Found the self-embedding DerivationStructure: "c a b b b b b -> b b c a b b b b b c c a c c a" c a b b b b b -> b b c a b b b b b c c a c c a by OverlapClosure OC 3"c a b b b b b -> b b c a b b a b b c c a c c a by OverlapClosure OC 3"c a b b b b b -> b b c a b b a a c a c c a by OverlapClosure OC 3"c a b b b b b -> a a b b a a c a c c a by OverlapClosure OC 2"c a b -> a c a by original rule (OC 1)""c a b b b b -> a b b a a c a c c a by OverlapClosure OC 2"c a b -> a c a by original rule (OC 1)""c a b b b -> b b a a c a c c a by OverlapClosure OC 3"c a b b b -> b b a c a b c c a by OverlapClosure OC 3"c a b b b -> a a b b c c a by OverlapClosure OC 3"c a b b b -> a a a c a by OverlapClosure OC 2"c a b -> a c a by original rule (OC 1)""c a b b -> a a c a by OverlapClosure OC 2"c a b -> a c a by original rule (OC 1)""c a b -> a c a by original rule (OC 1)""""a -> b b c by original rule (OC 1)"""a a b -> b b a c a by OverlapClosure OC 2"a -> b b c by original rule (OC 1)""c a b -> a c a by original rule (OC 1)""""c a b -> a c a by original rule (OC 1)"""""a -> b b c by original rule (OC 1)"""a -> b b c by original rule (OC 1)"""a -> b by original rule (OC 1)" ---------------------------------------- (2) NO
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