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SRS Standard pair #516974477
details
property
value
status
complete
benchmark
size-12-alpha-3-num-270.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n026.star.cs.uiowa.edu
space
Waldmann_07_size12
run statistics
property
value
solver
MnM 3.18b
configuration
default
runtime (wallclock)
1.30402517319 seconds
cpu usage
3.68804462
max memory
8.264704E8
stage attributes
key
value
output-size
1445
starexec-result
NO
output
/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO After renaming modulo the bijection { a ↦ 0, b ↦ 1, c ↦ 2 }, it remains to prove termination of the 3-rule system { 0 ⟶ , 0 1 ⟶ 2 0 , 2 2 ⟶ 1 1 2 1 0 } The system was reversed. After renaming modulo the bijection { 0 ↦ 0, 1 ↦ 1, 2 ↦ 2 }, it remains to prove termination of the 3-rule system { 0 ⟶ , 1 0 ⟶ 0 2 , 2 2 ⟶ 0 1 2 1 1 } Loop of length 17 starting with a string of length 6 using right expansion and the encoding { 0 ↦ a, 1 ↦ b, ... }: .cc.acac rule cc-> abcbb at position 0 .abcbb.acac rule ba-> ac at position 4 .abcbac.cac rule a-> at position 4 .abcbc.cac rule cc-> abcbb at position 4 .abcbabcbb.ac rule ba-> ac at position 3 .abcacbcbb.ac rule a-> at position 3 .abccbcbb.ac rule ba-> ac at position 7 .abccbcbac.c rule ba-> ac at position 6 .abccbcacc.c rule a-> at position 6 .abccbccc.c rule cc-> abcbb at position 5 .abccbabcbbc.c rule ba-> ac at position 4 .abccacbcbbc.c rule cc-> abcbb at position 10 .abccacbcbbabcbb. rule ba-> ac at position 9 .abccacbcbacbcbb. rule ba-> ac at position 8 .abccacbcaccbcbb. rule a-> at position 8 .abccacbcccbcbb. rule cc-> abcbb at position 7 .abccacbabcbbcbcbb. rule ba-> ac at position 6 .abccacacbcbbcbcbb.
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