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SRS Standard pair #516974507
details
property
value
status
complete
benchmark
size-12-alpha-3-num-83.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n094.star.cs.uiowa.edu
space
Waldmann_07_size12
run statistics
property
value
solver
MnM 3.18b
configuration
default
runtime (wallclock)
1.8749461174 seconds
cpu usage
5.613925734
max memory
9.29865728E8
stage attributes
key
value
output-size
1282
starexec-result
NO
output
/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- NO After renaming modulo the bijection { a ↦ 0, b ↦ 1, c ↦ 2 }, it remains to prove termination of the 4-rule system { 0 ⟶ , 0 0 ⟶ 1 0 1 2 , 2 ⟶ , 2 1 ⟶ 0 2 } Loop of length 18 starting with a string of length 8 using right expansion and the encoding { 0 ↦ a, 1 ↦ b, ... }: .cb.bbbbab rule cb-> ac at position 0 .ac.bbbbab rule cb-> ac at position 1 .aac.bbbab rule aa-> babc at position 0 .babcc.bbbab rule cb-> ac at position 4 .babcac.bbab rule cb-> ac at position 5 .babcaac.bab rule aa-> babc at position 4 .babcbabcc.bab rule a-> at position 5 .babcbbcc.bab rule cb-> ac at position 7 .babcbbcac.ab rule c-> at position 8 .babcbbca.ab rule aa-> babc at position 7 .babcbbcbabc.b rule cb-> ac at position 6 .babcbbacabc.b rule c-> at position 7 .babcbbaabc.b rule aa-> babc at position 6 .babcbbbabcbc.b rule a-> at position 7 .babcbbbbcbc.b rule cb-> ac at position 8 .babcbbbbacc.b rule c-> at position 9 .babcbbbbac.b rule cb-> ac at position 9 .babcbbbbaac. rule aa-> babc at position 8 .babcbbbbbabcc.
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