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SRS Standard pair #516974825
details
property
value
status
complete
benchmark
size-12-alpha-3-num-493.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n183.star.cs.uiowa.edu
space
Waldmann_07_size12
run statistics
property
value
solver
MnM 3.18b
configuration
default
runtime (wallclock)
0.74393415451 seconds
cpu usage
1.419093956
max memory
5.4276096E8
stage attributes
key
value
output-size
1349
starexec-result
NO
output
/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO After renaming modulo the bijection { a ↦ 0, b ↦ 1, c ↦ 2 }, it remains to prove termination of the 2-rule system { 0 0 ⟶ 1 , 1 0 2 ⟶ 2 2 0 0 0 0 } Loop of length 16 starting with a string of length 11 using right expansion and the encoding { 0 ↦ a, 1 ↦ b, ... }: .aa.acaaccacc rule aa-> b at position 0 .b.acaaccacc rule bac-> ccaaaa at position 0 .ccaaaa.aaccacc rule aa-> b at position 2 .ccbaa.aaccacc rule aa-> b at position 4 .ccbab.accacc rule bac-> ccaaaa at position 4 .ccbaccaaaa.cacc rule bac-> ccaaaa at position 2 .ccccaaaacaaaa.cacc rule aa-> b at position 5 .ccccabacaaaa.cacc rule bac-> ccaaaa at position 5 .ccccaccaaaaaaaa.cacc rule aa-> b at position 9 .ccccaccaabaaaa.cacc rule aa-> b at position 11 .ccccaccaababa.cacc rule bac-> ccaaaa at position 11 .ccccaccaabaccaaaa.acc rule bac-> ccaaaa at position 9 .ccccaccaaccaaaacaaaa.acc rule aa-> b at position 18 .ccccaccaaccaaaacaab.acc rule bac-> ccaaaa at position 18 .ccccaccaaccaaaacaaccaaaa.c rule aa-> b at position 21 .ccccaccaaccaaaacaaccaba.c rule bac-> ccaaaa at position 21 .ccccaccaaccaaaacaaccaccaaaa.
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