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SRS Standard pair #516974873
details
property
value
status
complete
benchmark
size-12-alpha-3-num-470.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n078.star.cs.uiowa.edu
space
Waldmann_07_size12
run statistics
property
value
solver
MnM 3.18b
configuration
default
runtime (wallclock)
4.2814950943 seconds
cpu usage
15.17608927
max memory
2.564612096E9
stage attributes
key
value
output-size
85000
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES After renaming modulo the bijection { a ↦ 0, b ↦ 1, c ↦ 2 }, it remains to prove termination of the 3-rule system { 0 0 ⟶ , 1 1 ⟶ 0 1 2 , 2 2 ⟶ 1 1 1 } Applying the dependency pairs transformation. Here, ↑ marks so-called defined symbols. After renaming modulo the bijection { (1,↑) ↦ 0, (1,↓) ↦ 1, (0,↑) ↦ 2, (2,↓) ↦ 3, (2,↑) ↦ 4, (0,↓) ↦ 5 }, it remains to prove termination of the 9-rule system { 0 1 ⟶ 2 1 3 , 0 1 ⟶ 0 3 , 0 1 ⟶ 4 , 4 3 ⟶ 0 1 1 , 4 3 ⟶ 0 1 , 4 3 ⟶ 0 , 5 5 →= , 1 1 →= 5 1 3 , 3 3 →= 1 1 1 } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 ↦ ⎛ ⎞ ⎜ 1 1 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 1 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 2 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 3 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 4 ↦ ⎛ ⎞ ⎜ 1 1 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 5 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ After renaming modulo the bijection { 0 ↦ 0, 1 ↦ 1, 3 ↦ 2, 4 ↦ 3, 5 ↦ 4 }, it remains to prove termination of the 8-rule system { 0 1 ⟶ 0 2 , 0 1 ⟶ 3 , 3 2 ⟶ 0 1 1 , 3 2 ⟶ 0 1 , 3 2 ⟶ 0 , 4 4 →= , 1 1 →= 4 1 2 , 2 2 →= 1 1 1 } Applying sparse tiling TROC(2) [Geser/Hofbauer/Waldmann, FSCD 2019]. After renaming modulo the bijection { (5,0) ↦ 0, (0,1) ↦ 1, (1,1) ↦ 2, (0,2) ↦ 3, (2,1) ↦ 4, (1,2) ↦ 5, (2,2) ↦ 6, (1,4) ↦ 7, (2,4) ↦ 8, (1,6) ↦ 9, (2,6) ↦ 10, (5,3) ↦ 11, (3,1) ↦ 12, (3,2) ↦ 13, (3,4) ↦ 14, (3,6) ↦ 15, (0,4) ↦ 16, (0,6) ↦ 17, (4,4) ↦ 18, (4,1) ↦ 19, (5,4) ↦ 20, (5,1) ↦ 21 }, it remains to prove termination of the 72-rule system { 0 1 2 ⟶ 0 3 4 , 0 1 5 ⟶ 0 3 6 , 0 1 7 ⟶ 0 3 8 , 0 1 9 ⟶ 0 3 10 , 0 1 2 ⟶ 11 12 , 0 1 5 ⟶ 11 13 , 0 1 7 ⟶ 11 14 , 0 1 9 ⟶ 11 15 , 11 13 4 ⟶ 0 1 2 2 , 11 13 6 ⟶ 0 1 2 5 , 11 13 8 ⟶ 0 1 2 7 , 11 13 10 ⟶ 0 1 2 9 , 11 13 4 ⟶ 0 1 2 , 11 13 6 ⟶ 0 1 5 , 11 13 8 ⟶ 0 1 7 , 11 13 10 ⟶ 0 1 9 , 11 13 4 ⟶ 0 1 , 11 13 6 ⟶ 0 3 , 11 13 8 ⟶ 0 16 , 11 13 10 ⟶ 0 17 , 16 18 19 →= 1 , 16 18 18 →= 16 , 7 18 19 →= 2 , 7 18 18 →= 7 ,
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