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SRS Standard pair #516975047
details
property
value
status
complete
benchmark
size-12-alpha-3-num-209.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n059.star.cs.uiowa.edu
space
Waldmann_07_size12
run statistics
property
value
solver
MnM 3.18b
configuration
default
runtime (wallclock)
15.6008939743 seconds
cpu usage
60.278708726
max memory
6.74863104E9
stage attributes
key
value
output-size
1592
starexec-result
NO
output
/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- NO After renaming modulo the bijection { a ↦ 0, b ↦ 1, c ↦ 2 }, it remains to prove termination of the 4-rule system { 0 ⟶ , 0 1 ⟶ 1 1 0 2 0 , 1 ⟶ , 2 2 1 ⟶ } Loop of length 24 starting with a string of length 8 using right expansion and the encoding { 0 ↦ a, 1 ↦ b, ... }: .ab.bbbbbb rule ab-> bbaca at position 0 .bbaca.bbbbbb rule ab-> bbaca at position 4 .bbacbbaca.bbbbb rule b-> at position 4 .bbacbaca.bbbbb rule b-> at position 4 .bbacaca.bbbbb rule a-> at position 4 .bbacca.bbbbb rule ab-> bbaca at position 5 .bbaccbbaca.bbbb rule ccb-> at position 3 .bbabaca.bbbb rule ab-> bbaca at position 6 .bbabacbbaca.bbb rule b-> at position 6 .bbabacbaca.bbb rule b-> at position 6 .bbabacaca.bbb rule a-> at position 6 .bbabacca.bbb rule ab-> bbaca at position 7 .bbabaccbbaca.bb rule ccb-> at position 5 .bbababaca.bb rule ab-> bbaca at position 4 .bbabbbacaaca.bb rule a-> at position 8 .bbabbbacaca.bb rule a-> at position 8 .bbabbbacca.bb rule ab-> bbaca at position 9 .bbabbbaccbbaca.b rule ccb-> at position 7 .bbabbbabaca.b rule ab-> bbaca at position 6 .bbabbbbbacaaca.b rule a-> at position 10 .bbabbbbbacaca.b rule a-> at position 10 .bbabbbbbacca.b rule ab-> bbaca at position 11 .bbabbbbbaccbbaca. rule ccb-> at position 9 .bbabbbbbabaca. rule ab-> bbaca at position 8 .bbabbbbbbbacaaca.
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